C(15, 7)
(15 * 14 * 13 * 12 * 11 * 10 * 9)/(7 * 6 * 5 * 4 * 3 * 2 * 1) = 6435 groups
Answer:
The amount of Polonium-210 left in his body after 72 days is 6.937 μg.
Step-by-step explanation:
The decay rate of Polonium-210 is the following:
(1)
Where:
N(t) is the quantity of Po-210 at time t =?
N₀ is the initial quantity of Po-210 = 10 μg
λ is the decay constant
t is the time = 72 d
The decay rate is 0.502%, hence the quantity that still remains in Alexander is 99.498%.
First, we need to find the decay constant:
(2)
Where t(1/2) is the half-life of Po-210 = 138.376 days
By entering equation (2) into (1) we have:
Therefore, the amount of Polonium-210 left in his body after 72 days is 6.937 μg.
I hope it helps you!
Answer:
2.36
Step-by-step explanation:
Step-by-step explanation:
The correct answer
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