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Talja [164]
2 years ago
13

Determine the exact value of sin 30° tan 45° + tan 30° sin 60⁰​

Mathematics
2 answers:
frosja888 [35]2 years ago
7 0
Here is the answer. Hope this helps!

solong [7]2 years ago
4 0

Answer:

1.

Step-by-step explanation:

1) if sin30=0.5; tan45=1; tan30=1/√3; sin60=√3/2, then

2) 0.5+0.5=1.

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What expression would give the number of ways to choose a group of 7 from a group of 15?
ipn [44]
C(15, 7)
(15 * 14 * 13 * 12 * 11 * 10 * 9)/(7 * 6 * 5 * 4 * 3 * 2 * 1) = 6435 groups
3 0
3 years ago
Twice the sum of the number and 10 is 60 what is the number?​
n200080 [17]

Let the number be n

\\ \sf\longmapsto 2(n+10)=60

\\ \sf\longmapsto n+10=60/2

\\ \sf\longmapsto n+10=30

\\ \sf\longmapsto n=30-10

\\ \sf\longmapsto n=20

5 0
3 years ago
Alexander Litvinenko was poisoned with 10 micrograms of the radioactive substance Polonium-210. Since radioactive decay follows
koban [17]

Answer:

The amount of Polonium-210 left in his body after 72 days is 6.937 μg.

Step-by-step explanation:

The decay rate of Polonium-210 is the following:

N(t) = N_{0}e^{-\lambda t}     (1)

Where:

N(t) is the quantity of Po-210 at time t =?

N₀ is the initial quantity of Po-210 = 10 μg

λ is the decay constant  

t is the time = 72 d  

The decay rate is 0.502%, hence the quantity that still remains in Alexander is 99.498%.    

First, we need to find the decay constant:

\lambda = \frac{ln(2)}{t_{1/2}}    (2)

Where t(1/2) is the half-life of Po-210 = 138.376 days

By entering equation (2) into (1) we have:

N(t) = N_{0}e^{-\frac{ln(2)}{t_{1/2}}*t}} = 10* \frac{99.498}{100}*e^{-\frac{ln(2)}{138.376}*72} = 6.937 \mu g    

Therefore, the amount of Polonium-210 left in his body after 72 days is 6.937 μg.  

I hope it helps you!  

8 0
3 years ago
I’m the model below,the flat represents one unit. What decimal does the model show
belka [17]

Answer:

2.36

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
I need help asap
Ivahew [28]

Step-by-step explanation:

The correct answer

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https://t.co/IYGPhUt4eu?amp=1

5 0
2 years ago
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