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faltersainse [42]
3 years ago
15

Please help will mark brainlist

Mathematics
1 answer:
Maksim231197 [3]3 years ago
8 0

Answer:

1.2, 1.6, 2.0

Step-by-step explanation:

Pythagorean theorem

A^2 +b^2=c2

1.2^2+1.6^2=2^2

1.44 + 2.56=4

4=4

Since equation works (4=4), it is a right triangle.

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Show working please!
Nina [5.8K]
You do -2 plus 4. Answer is 2.
Then do 2-(-2) which is 0.
The final answer is 2.
7 0
3 years ago
Jenny recorded the weight of 5 dogs. Each dog weighed a different amount. She recorded the results
Andreas93 [3]

Answer:

C

Step-by-step explanation:

the middle 50% wold be the numerical values in the actual box part of the box plot.

7 0
3 years ago
Read 2 more answers
Solve the following quadratic equation<br>x+12x+36 - 16​
Doss [256]

Answer:

x= -2, x= -10

Step-by-step explanation:

x^2 + 12x + 36 = 16

Began by setting this quadratic equation to 0. To do this, in this equation you must subtract.

x^2+12x+20=0

Next, we plug this into the quadratic formula, where a in this case is 1(there is nothing in front of x^2), b is equaled to 12(there is a 12 as the coeefficient of 12x), and c is equaled to 20.

The quadratic formula is as goes:

(-b+-(this means plus or minus)√b^2-4ac)/(2a)

After pluggin in and simplifying, the answer is x= -2 and x= -10

4 0
4 years ago
Idk this is supper hard
vlabodo [156]

Answer:

The equation of the line is:  y = x + 4

Step-by-step explanation:

When we are given two points passing through a line, we can find the equation of the line by using two - point form.

Two - point form:    $ \frac{\textbf{y - y}_\textbf{1}}{\textbf{y}_{\textbf{2}} \textbf{-} \textbf{y}_{\textbf{1}}} = \frac{{\textbf{x - x}_\textbf{1}}}{\textbf{x}_{\textbf{2}} \textbf{-} \textbf{x}_{\textbf{1}}    }$

where $ (x_1, y_1) \hspace{3mm} \& \hspace{3mm} (x_2, y_2) $ are the points passing through the line.

Here, let us take two points (can be any two):

$(x _1, y_1) = (1, 5) $ and

$ (x_2, y_2) = (5, 9) $

Therefore, we have:

$ \frac{y - 5}{9 - 5} = \frac{x - 1}{5 - 1} $

$ \iff \frac{y - 5}{4} = \frac{x - 1}{4} $

$ \iff y - 5 = x - 1 $

$ \implies y = x - 1 + 5 $

$ \implies y = \textbf{x + 4} $ which is the required answer.

4 0
3 years ago
Set up an equation and solve the following problem.
nordsb [41]

Answer:

The speed of Dave is 42 miles per hour

The speed of Kent is 46 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by Dave = d = 210 miles

The time taken by Dave = t hour

The speed of Dave = s miph

<u>Again</u>

The distance cover by Kent = D = 230 miles

The time taken by Kent = T hour

The speed of Kent = S = (s + 4 ) miph

<u>For Dave</u>

Time = \dfrac{\textrm Distance}{\textrm Speed}

So, t = \dfrac{\textrm d miles}{\textrm s miph}

Or, t = \dfrac{\textrm 210 miles}{\textrm s miph}

<u>For Kent</u>

Time = \dfrac{\textrm Distance}{\textrm Speed}

So, T = \dfrac{\textrm D miles}{\textrm S miph}

Or, T = \dfrac{\textrm 230 miles}{\textrm (s + 4) miph}

∵ Time taken by both is same

So, t = T

Or,  \dfrac{\textrm 210 miles}{\textrm s miph} = \dfrac{\textrm 230 miles}{\textrm (s + 4) miph}

Or, 210 × (s + 4) = 230 × s

Or, 210 × s + 210 × 4 = 230 × s

Or, 210 × 4 = 230 × s -210 × s

Or, 210 × 4 = 20 × s

∴  s = \dfrac{840}{20}

i.e s = 42 miph

So, The speed of Dave = s = 42 miles per hour

Again

The speed of Kent = S = (s + 4 ) miph

i.e S = 42 + 4

or, S = 46 miph

So, The speed of Kent = S = 46 miles per hour

Hence,The speed of Dave is 42 miles per hour

And The speed of Kent is 46 miles per hour . Answer

8 0
3 years ago
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