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suter [353]
4 years ago
13

Mary takes a sightseeing tour on a helicopter that can fly 450 miles against a 35 mph headwind. In the same amount of time it ca

n travel 702 miles with a 35 mph tailwind. Find the speed of the helicopter.
Mathematics
1 answer:
monitta4 years ago
5 0

Answer:

V = 160mph

Step-by-step explanation:

We need to start from the formula of speed: V=d/t

We have two travels, with and against the wind, both done in the same time.

Clearing t from the formula, we will have: t=d/V2

450miles/V-35mph (speed of the wind is subtracted)

702miles/V+35mph (speed of the wind is subtracted)

Now, we find V:

450miles/V-35mph = 702miles/V+35

450*V+35 = 702*V-35

450V+15,750 = 702V-24,570

702V-450V = 15,750 + 24,570

252V = 40,320

V = 40,320/252

V = 160mph

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Anna [14]

Answer:

Addition property of Equality

Step-by-step explanation:

Adding same quantity to both sides of equation is called addition property of equality

3 0
3 years ago
A semi-circle with a diameter of 4 is rotated around its diameter one full rotation, what is the volume of the solid generated b
iris [78.8K]

The volume of the solid generated by the revolution is 33.5 cubic units.

<u>Step-by-step explanation:</u>

It is given that, the diameter of the semi-circle is 4 and it is rotated to one full rotation around its diameter.

A solid generated when a semicircle is being rotated about its diameter is called a "SPHERE".

Therefore, the volume of the solid generated by the revolution is the volume of the sphere.

The formula for volume of the sphere is given by,

Volume of sphere = (4/3)πr³

where, r is the radius and π has the default value of 3.14

Here, the given diameter is 4.

To find the radius = diameter/2

radius = 4/2 = 2.

Now, to calculate volume of sphere substitute r=2 and π=3.14

volume of the sphere = (4/3)×3.14×2³

⇒ (4/3)×3.14×8

⇒ 100.48 / 3

⇒ 33.49 (approximately 33.5)

Therefore, the volume of the solid generated by the revolution is 33.5 cubic units.

8 0
3 years ago
1 pt
pogonyaev
5,000 I’m pretty positive !
6 0
3 years ago
Read 2 more answers
Let C(x) be the statement "x has a cat," let D(x) be the statement "x has a dog," and let F(x) be the statement "x has a ferret.
jek_recluse [69]

Answer:

\mathbf{a)} \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\\\mathbf{b)} \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee \; F(x)\\\mathbf{c)} \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)\\\mathbf{d)} \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)\\\mathbf{e)} \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

Step-by-step explanation:

Let X be a set of all students in your class. The set X is the domain. Denote

                                        C(x) -  ' \text{$x $ has a cat}'\\D(x) -  ' \text{$x$ has a dog}'\\F(x) -  ' \text{$x$ has a ferret}'

\mathbf{a)}

Consider the statement '<em>A student in your class has a cat, a dog, and a ferret</em>'. This means that \exists x \in X so that all three statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                         \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)

\mathbf{b)}

Consider the statement '<em>All students in your class have a cat, a dog, or a ferret.' </em>This means that \forall x \in X at least one of the statements C(x), D(x) and F(x) is true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                        \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee F(x)

\mathbf{c)}

Consider the statement '<em>Some student in your class has a cat and a ferret, but not a dog.' </em>This means that \exists x \in X so that the statements C(x), F(x) are true and the negation of the statement D(x) . We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                      \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)

\mathbf{d)}

Consider the statement '<em>No student in your class has a cat, a dog, and a ferret..' </em>This means that \forall x \in X none of  the statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as a negation of the statement in the part a), as follows

\neg \left( \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\right) \iff \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)

\mathbf{e)}

Consider the statement '<em> For each of the three animals, cats, dogs, and ferrets, there is a student in your class who has this animal as a pet.' </em>

This means that for each of the statements C, F and D there is an element from the domain X so that each statement holds true.

We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

           \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

5 0
4 years ago
What property is (3x10)x8x(10x8)
mixer [17]

distributinve, multiplying from parenthesece

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