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suter [353]
3 years ago
13

Mary takes a sightseeing tour on a helicopter that can fly 450 miles against a 35 mph headwind. In the same amount of time it ca

n travel 702 miles with a 35 mph tailwind. Find the speed of the helicopter.
Mathematics
1 answer:
monitta3 years ago
5 0

Answer:

V = 160mph

Step-by-step explanation:

We need to start from the formula of speed: V=d/t

We have two travels, with and against the wind, both done in the same time.

Clearing t from the formula, we will have: t=d/V2

450miles/V-35mph (speed of the wind is subtracted)

702miles/V+35mph (speed of the wind is subtracted)

Now, we find V:

450miles/V-35mph = 702miles/V+35

450*V+35 = 702*V-35

450V+15,750 = 702V-24,570

702V-450V = 15,750 + 24,570

252V = 40,320

V = 40,320/252

V = 160mph

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(1) \frac{p_{j} }{1-d_{i}p_{i}  } , if j \neq i, and

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this gives us:

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Solution to Part (1):

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this means that

P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)}  = \frac{P(C_{j} )}{P(A)}  = \frac{p_{j} }{1-d_{i}p_{i}  }

as needed so part one is solved.

Solution to Part(2):

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remember that:

P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}

this implies that:

P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )

so we just need to combine the above relations to get:

P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i}  }

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3 years ago
In the equation z= x/y – y/x, take x as the numbers given below find number z.
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The speed of a boat in still water is 10 km/hr. If it can travel 78 km downstream and 42 km upstream in the same time, the speed
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5x-10=3x+40
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