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kolezko [41]
2 years ago
5

Which statement is true for all parallelograms? (1 point)

Mathematics
1 answer:
Aloiza [94]2 years ago
8 0

The opposite sides are equal in length.

Step-by-step explanation:

Opposite sides of a parallelogram must be congruent. This is a property of all parralelograms.

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Give the number to which the Fourier series converges at a point of discontinuity of f.
quester [9]

Answer:

The Fourier series of f(x) converges to 3 at the points x= π+2kπ, where k is an integer.

Step-by-step explanation:

First, recall that the function f(x) is extended 2π periodic to the whole real line, in order to obtain a valid Fourier expansion. Remember that a Fourier series is formed by a sines and cosines, which are 2π-periodic.

So, the 2π-periodic expansion of f(x) is discontinuous at the points π+2kπ, in particular π and -π. Check the attached figure to a better understanding.

Now, the Dirichlet theorem on the convergence of a Fourier series tells us that the series converges to the function at the points of continuity, and at points of discontinuity the sum of the series is

\frac{f(x_0+)+f(x_0-)}{2}.

Here we understand the notation f(x+) and f(x-) as

f(x_0+) = \lim_{x\rightarrow x_0}f(x), x>x_0

and

f(x_0-) = \lim_{x\rightarrow x_0}f(x), x.

In this particular case

f(\pi-) = \lim_{x\rightarrow \pi}(3-2x) = 3-2\pi, x.

For the limit f(\pi+) = \lim_{x\rightarrow \pi}(3-2x), with x>\pi recall that our function is 2π-periodic, so the values of f near π, with x>π are the same when x is near -π and x>-π. Again, check the attached figure. So,

f(\pi+) = \lim_{x\rightarrow \pi}(3-2x) = 3+2\pi, x.

Thus,

\frac{f(\pi+)+f(\pi-)}{2} = \frac{3+2\pi +3-2\pi}{2} = \frac{6}{2} =3.

Note: In the attached figure we only have drawn three repetitions of the 2π-periodic extension of f, recall that the extension is <em>ad infinitum</em>. Also, the points drawn in the dotted lines are the sum of the series at the points of discontinuity.

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