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3 years ago

Please answer quick!

Mathematics

2 answers:

tatuchka [14]3 years ago

3 0

4 * (25 * 1.2) = (4 * 25) * 1.2

irga5000 [103]3 years ago

3 0

Answer:

(4 x 25 ) in the first box and in the second box 1.2

Step-by-step explanation:

i just did the quiz and got 100% , your welcome.

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padilas [110]

Hope this helps you.

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3 years ago

10x-9 y = 24<br> y=x-2<br> x=<br> Y=

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3 years ago

20. Sofia paid $11.80 for a pen, a marker, and a binder. The marker cost $0.80 more than the pen. The binder cost 4 times as muc

7nadin3 [17]

Answer:

$1.30

Step-by-step explanation:

Let x = the cost of the pencil

Let x + .80 = the cost of the pen

Let 4(x + .80) = the cost of the binder

x + x + .80 + 4(x + .80) = 11.80

2x + .80 + 4x + 3.20 = 11.80

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7 0

1 year ago

Read 2 more answers

What is the answer for this algebra question 4(2n-5)=3n+10

miss Akunina [59]

$4(2n-5)=3n+10\\\\
8n-20=3n+10\ \ \ |Subtract\ 3n\\\\
5n-20=10\ \ \ Add\ 20\\\\
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4 0

3 years ago

Read 2 more answers

A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num

yKpoI14uk [10]

Answer: hypotenuse = $c^{2} + b^{2}$

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side ( $s_{1},s_{2}$ ) of the right triangle, .i.e.:

$h^{2} = s_{1}^{2} + s_{2}^{2}$

In this question:

$s_{1}$ = $c^{2}-b^{2}$

$s_{2} =$ 2bc

Substituing and taking square root to find hypotenuse:

$h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}$

Calculating:

$h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}$

$h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}$

$c^{4}+b^{4}+2b^{2}c^{2}$ = $(c^{2}+b^{2})^{2}$ , then:

$h=\sqrt{(c^{2}+b^{2})^{2}}$

$h=(c^{2}+b^{2})$

Hypotenuse for the right-angled triangle is $h=(c^{2}+b^{2})$ units

3 0

3 years ago