The fertilizer contains 7.90 % P by mass.
<em>Assume</em> you have 100 g of fertilizer.
<em>Mass of P₄O₁₀</em> = 100 g fertilizer × 18.1 g P₄O₁₀/100 g fertilizer = 18.1 g P₄O₁₀
<em>M_r of P₄O₁₀</em> = 4 × 30.97 + 10× 16.00 = 123.88 + 160.00 = 283.88
<em>Mass of P</em> = 18.1 g P₄O₁₀ × (123.88 g P/283.88 g P₄O₁₀) = 7.90 g P
<em>Mass % P</em> = mass/total mass × 100 % = 7.90 g /100 g × 100 % = 7.90 %
Prepare a 1% copper sulfate solution. To make this solution, weigh 1 gram of copper sulfate (CuSO4 ·5H2O), dissolve in a small amount of distilled water in a 100 ml volumetric flask and bring to volume. Label this as 1% copper sulfate solution.
Hi just wanted to say thank you for answering my question and I wanted to help so I believe the answer is A.
Answer:
Explanation:
Hello!
In this case, since the molarity of a solution is calculated by diving the moles of solute by the volume of solution in liters, we first compute the moles of barium hydroxide in 35.5 g as shown below:
Then, the liters of solution:
Finally, the molarity turns out:
Best regards!
1. combustion
2.decompostioni
3.synthesids
4double replacement
5.single replacement
