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arlik [135]
2 years ago
9

Which of the following statements about trash in the United States is FALSE? Each person produces about 2 kg of trash per day. T

here is nothing we can do to reduce the amount of trash we throw away. Most of our trash ends up in landfills. Some of the things we throw away are very hazardous.
Chemistry
1 answer:
andrew11 [14]2 years ago
4 0

Answer:

There is nothing we can do to reduce the amount of trash we throw away.

Explanation:

We can reuse and recycle the trash that we throw away, so we can do something to reduce the amount of trash that we throw

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the purpose of the ____ system prevent foreign substances from entering the body and to attack foreign substances that are in th
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Immune System is the answer.
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How many litres (L) of oxygen at STP can be obtained from 110 g of potassium chlorate? [R=0.0821 L.atm/K.mol]
lisabon 2012 [21]
Balance the equation first:

2 KClO3 (s) ---> 2 KCl (s) + 3 O2 (g)

Moles of KClO3 =  110 / 122.5 = 0.89

Following the balanced chemical equation:
We can say moles of O2 produce =  \frac{3}{2} x moles of KClO3

So, O2 = (3 / 2) x  0.89

= 1.34 moles

So, Volume at STP = nRT / P

T = <span>273.15 K
P = 1 atm

So, V = (1.34 x 0.0821 x 273.15) / 1  =  30.2 L</span>
3 0
3 years ago
What is the complete balanced equation for the reaction that occurs when lithium carbonate (Li2CO3) is heated?
Fed [463]
When heating lithium carbonate (Li2CO3), it will dissociate to Li2O and Co2. So the balanced chemical equation of this reaction is Li2CO3 = Li2O + CO2. 
7 0
3 years ago
What pressure is exerted on the bottom of a 0.500-m-wide by 0.900-m-long gas tank that can hold 50.0 kg of gasoline by the weigh
Natasha_Volkova [10]

Answer:

1088.89 Pa

Explanation:

According to the Newton's second law of motion:-

Force=Mass\times Acceleration

Mass = 50.0 kg

Acceleration = g = 9.81 m/s²

So,  

Force=50.0\times 9.8\ kgm/s^2

Force = 490 N

Area of the base = length\times breath = 0.500\times 0.900 m² = 0.45 m²

<u>Pressure = Force/Area = \frac{490\ N}{0.45\ m^2} = 1088.89 Pa</u>

8 0
3 years ago
1. Calculate the energy change (q) of the surroundings (water) using the enthalpy equation
Rasek [7]

Answer:

Q1: 728.6 J.

Q2:

a) 668.8 J.

b) 0.3495 J/g°C.

Explanation:

<em>Q1: Calculate the energy change (q) of the surroundings (water) using the enthalpy equation:</em>

  • The amount of heat absorbed by water = Q = m.c.ΔT.

where, m is the mass of water (m = d x V = (1.0 g/mL)(24.9 mL) = 24.9 g).

c is the specific heat capacity of liquid water = 4.18 J/g°C.

ΔT is the temperature difference = (final T - initial T = 32.2°C - 25.2°C = 7.0°C).

<em>∴ The amount of heat absorbed by water = Q = m.c.ΔT</em> = (24.9 g)(4.18 J/g°C)(7.0°C) = 728.6 J.

<em>Q2:  Calculate the energy change (q) of the surroundings (water) using the enthalpy equation </em>

<em>qwater = m × c × ΔT.  </em>

<em>We can assume that the specific heat capacity of water is 4.18 J / (g × °C) and the density of water is 1.00 g/mL. calculate the specific heat of the metal. Use the data from your experiment for the unknown metal in your calculation.</em>

<em></em>

a) First part: the energy change (q) of the surroundings (water):

  • The amount of heat absorbed by water = Q = m.c.ΔT.

where, m is the mass of water (m = d x V = (1.0 g/mL)(25 mL) = 25 g).

c is the specific heat capacity of liquid water = 4.18 J/g°C.

ΔT is the temperature difference = (final T - initial T = 31.6°C - 25.2°C = 6.4°C).

<em>∴ The amount of heat absorbed by water = Q = m.c.ΔT</em> = (25 g)(4.18 J/g°C)(6.4°C) = <em>668.8 J.</em>

<em>b) second part:</em>

<em>Q water = Q unknown metal. </em>

<em>Q unknown metal =  - </em>668.8 J. (negative sign due to the heat is released from the metal to the surrounding water).

<em>Q unknown metal =  - </em>668.8 J = m.c.ΔT.

m = 27.776 g, c = ??? J/g°C, ΔT = (final T - initial T = 31.6°C - 100.5°C = - 68.9°C).

<em>- </em>668.8 J = m.c.ΔT = (27.776 g)(c)( - 68.9°C) = - 1914 c.

∴ c = (<em>- </em>668.8)/(- 1914) = 0.3495 J/g°C.

<em></em>

3 0
3 years ago
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