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lidiya [134]
2 years ago
8

Anyone? please help asap i really want to finish this

Mathematics
1 answer:
Nesterboy [21]2 years ago
8 0

Answer:

Question 3: b \geq 2

Question 4: r < -5

Question 5: y \leq -6

Step-by-step explanation:

Question 3:

b + 2 \geq 4\\b + 2  -2 \geq 4 - 2\\b \geq 2\\

Question 4:

13 > 18 + r\\13 - 18 > 18 -18 + r\\\\-5 > r\\ r < -5sign flips when r switches sides

Question 5:

3y \leq 2y - 6\\3y - 2y \leq 2y - 2y - 6\\\\y \leq - 6\\

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QUESTION 10
adelina 88 [10]

Answer:

Step-by-step explanation:

A = L * W

A = 22

L = 2x + 1

W = 3x + 1

now we sub

22 = (2x + 1)(3x + 1)

22 = 6x^2 + 2x + 3x + 1

22 = 6x^2 + 5x + 1

6x^2 + 5x + 1 - 22 = 0

6x^2 + 5x - 21 = 0 <======part A

(3x + 7)(2x - 3) = 0

3x + 7 = 0          2x - 3 = 0

3x = -7               2x = 3

x = -7/3              x = 3/2

I believe that x = -7/3 is an extraneous solution because when u plug it into ur length and width u get a negative number....and I dont think the sides of ur rectangle have negative values, however, it does work in ur equation and it equals 22 when multiplied...so I am not 100% sure

length = 2x + 1.......2(3/2) + 1........3 + 1 = 4

width = 3x + 1......3(3/2) + 1......9/2 + 1......9/2 + 2/2 = 11/2 (or 5.5) meters <===

6 0
3 years ago
The gas tank on the back of a tanker truck can be equated to a cylinder with a diameter of 8 feet and a length of 19 feet. A gal
Leokris [45]

9514 1404 393

Answer:

  • driver's tank: 30,427 lb
  • farmer's tank: 12,811 lb

Step-by-step explanation:

The formula for the volume of a cylinder is ...

  V = πr^2·h . . . radius r, height h

The radius of the driver's tank is half its diameter, so is (8 ft)/2 = 4 ft. Then the volume of that tank is ...

  V = π(4 ft)^2·(19 ft) = 304π ft^3

Each cubic foot of gasoline has a mass of ...

  (1728 in^3/ft^3)(0.0262 lb/in^3) = 45.2736 lb/ft^3

Then the total mass in the driver's full tank is ...

  (304π ft^3)(45.2736 lb/ft^3) ≈ 43,238.3 lb

__

The farmer's tank is a scaled-down version of the driver's tank. It's volume will be scaled by the cube of the linear scale factor, so will be (2/3)^3 = 8/27 of the volume of the driver's tank.

The farmer's tank will hold a mass of (43,238.3 lb)(8/27) ≈ 12,811 lb.

The amount remaining in the driver's tank is 43,238 -12,811 = 30,427 lb.

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