a right triangle has a base that measures 39 inches and a height that measures 80 inches what is the length of the hypotense
1 answer:
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Hello!
Answer:
To solve, we will need to use Right-Triangle Trigonometry:
Begin by solving for angles ∠S and ∠R using tangent (tan = opp/adj)
tan ∠S = a / (1/2b)
tan ∠S = 3√5 / 14
tan ∠S ≈ 0.479
arctan 0.479 = m∠S (inverse)
m∠S and m∠R ≈ 25.6°
Use cosine to solve for the hypotenuse, or the missing side-length:
cos ∠S = 14 / x
x · cos (25.6) = 14
x = 14 / cos(25.6)
x ≈ 15.52
Both triangles are congruent, so we can go ahead and find the perimeter of the figure:
RS + RQ + QS = 28 + 15.52 + 15.52 = 59.04 units.
Hope this helped you! :)
To make the input-output table, we need to plug in the given vaues of x's in the equation to get their corresponding values of y.
Let's plug in x = -2 in y = 6x +5. So,
y = 6( -2) + 5 = -12 + 5 = -7
Similarly for x = 0, y= 6(0) + 5 = 5
For x = 1, y = 6(1) + 5 = 6 + 5 = 11
For x = 4, y = 6(4) + 5 = 24 + 5 = 29
For x= 5, y = 6(5) + 5 = 30 + 5 = 35.
I am attaching the input -output table from the above result.
Hope this helps you!
