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maw [93]
3 years ago
13

Whats the answer to this problem?

Mathematics
2 answers:
rewona [7]3 years ago
7 0

6m x 10m for the rectangle part.

Then the triangle is base x height/2=3 x 7/2= 21/2

But we have two of the same triangle, so we multiply 21/2 by 2, giving us 21.

21 + 60= 81m^2

Hope you get it!

Greeley [361]3 years ago
4 0

Answer:

81m²

Step-by-step explanation:

The area of the rectangular part is given by length × width;

i.e 6m × 10m = 60m²

The area of the triangular part is given by \frac{1}{2} × base × height

So it will be \frac{1}{2} × 6m × 7m = 21m²

Total area = Area of the composite figure = 60m² + 21m² = 81m²

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Questio
Olenka [21]

Answer:

  d = -1/3, 0

Step-by-step explanation:

Subtract the constant on the left, take the square root, and solve from there.

  (6d +1)^2 + 12 = 13 . . . . given

  (6d +1)^2 = 1 . . . . . . . . . .subtract 12

  6d +1 = ±√1 . . . . . . . . . . take the square root

  6d = -1 ±1 . . . . . . . . . . . .subtract 1

  d = (-1 ±1)/6 . . . . . . . . . . divide by 6

  d = -1/3, 0

_____

Using a graphing calculator, it is often convenient to write the function so the solutions are at x-intercepts. Here, we can do that by subtracting 13 from both sides:

  f(x) = (6x+1)^ +12 -13

We want to solve this for f(x)=0. The solutions are -1/3 and 0, as above.

4 0
3 years ago
The sum of 3y and 5 is 47
Daniel [21]

if 3y + 5 = 47

then

y=14

7 0
3 years ago
Someone help me please. I don't just want the answer, I need an explanation on how it's done too.​
NARA [144]

Answer:

Below.

Step-by-step explanation:

f) (a + b)^3 - 4(a + b)^2  

The (a+ b)^2 can be taken out to give:

= (a + b)^2(a + b - 4)

= (a + b)(a + b)(a + b - 4).

g)  3x(x - y) - 6(-x + y)

=  3x( x - y) + 6(x - y)

= (3x + 6)(x - y)

= 3(x + 2)(x - y).

h) (6a - 5b)(c - d) + (3a + 4b)(d - c)

=  (6a - 5b)(c - d) + (-3a - 4b)(c - d)

= -(c - d)(6a - 5b)(3a + 4b).

i)  -3d(-9a - 2b) + 2c (9a + 2b)

= 3d(9a + 2b) + 2c (9a + 2b)

=  3d(9a + 2b) + 2c (9a + 2b).

= (3d + 2c)(9a + 2b).

j)  a^2b^3(2a + 1) - 6ab^2(-1 - 2a)

=  a^2b^3(2a + 1) + 6ab^2(2a + 1)

= (2a + 1)( a^2b^3 + 6ab^2)

The GCF of a^2b^3 and  6ab^2 is ab^2, so we have:

(2a + 1)ab^2(ab + 6)

= ab^2(ab + 6)(2a + 1).

4 0
2 years ago
X <br> 2<br> +(y−7.5) <br> 2<br> = <br> 49<br> 9<br> ​ What is the radius?
Flura [38]

50 is the answer hugnfgh

8 0
3 years ago
Read 2 more answers
Find the inverse of square root f(n) = n – 3.
pogonyaev

Answer:

f'(n) = n + 3

Step-by-step explanation:

Given

f(n) = n - 3

Required

The inverse

f(n) = n - 3

Replace f(n) with y

y = n - 3

Swap positions of y and n

n = y - 3

Make y the subject

y = n + 3

Replace y with f'(n)

f'(n) = n + 3

4 0
3 years ago
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