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2 years ago

Ready Mathematics

Mathematics

1 answer:

Sergeu [11.5K]2 years ago

5 0

Answer:

Talking Ben Thinks It 7 cm

Step-by-step explanation:

7m Cause Ben Told me

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I just need someone to fill in all the answers

Masteriza [31]

Answer:

1. 2

2. 25

3. 1/3

I'm in 8th grade so not 100% sure about these

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2 years ago

What is the value of the expression below when x = 3?<br> 10x2 – 7x + 10

QveST [7]

Answer:

Step-by-step explanation:

To find the value of $10x^2 – 7x + 10$ , when x = 3, simply plug in the value of x in the expression and solve as follows:

$10(3)^2 – 7(3) + 10$

$10(9) – 21 + 10$

$90 – 21 + 10$

$79$

The value of $10x^2 – 7x + 10$ , when x = 3, is 79

5 0

3 years ago

Work out the area of a rectangle with base, b = 20mm and perimeter, P = 60mm.

skelet666 [1.2K]

base+perimeter

20mm+60mm

=80mm

8 0

2 years ago

If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle?

kondaur [170]

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

Solution:

The endpoints of the diameter of a circle are (–8, –6) and (–4, –14).

Center of the circle = Mid point of the diameter

Mid point formula:

$$P(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

Here, $x_1=-8, y_1=-6, x_2=-4, y_2=-14$

$$P(x, y) =\left(\frac{-8-4}{2}, \frac{-6-14}{2}\right)$

$$P(x, y) =\left(\frac{-12}{2}, \frac{-20}{2}\right)$

$$P(x, y) =(-6, -10)$

Center of the circle = (–6, –10)

Radius is the distance between center and any endpoint of the diameter.

To calculate the radius using distance formula.

$r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Here, $x_1=-6, y_1=-10, x_2=-8, y_2=-6$

$r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}$

$r=\sqrt{(-8+6)^{2}+(-6+10)^{2}}$

$r=\sqrt{(-2)^{2}+(4)^{2}}$

$r=\sqrt{20}$ units

The standard form of the equation of a circle is

$(x-a)^{2}+(y-b)^{2}=r^{2}$ , where (a, b) are center and r is the radius.

Here, center = (–6, –10) and $r=\sqrt{20}$

$(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}$

$(x+6)^{2}+(y+10)^{2}=20$

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

4 0

2 years ago

Unit 3 Mid - Assessment

Sophie [7]

Y=1x-7 is the equation and -7 is the value of B

3 0

3 years ago