You'll have to do the actual multiplication here:
3(n+2)(4n+1) 1 4n^2 + n + 8n + 2
-------------------- = ----- * ---------------------------
6 2 1
or (1/2) (4n^2 + 9n + 2), which, after mult., becomes
(1/2)(4n^2) + (1/2)(9n) + 1
This simplifies to 2n^2 + (9/2)n + 1
Therefore, write (1/2) in the first box and (1) in the second box.
Too long busy make it shorter
wheee
Compute each option
option A: simple interest
simple interest is easy
A=I+P
A=Final amount
I=interest
P=principal (amount initially put in)
and I=PRT
P=principal
R=rate in decimal
T=time in years
so given
P=15000
R=3.2% or 0.032 in deecimal form
T=10
A=I+P
A=PRT+P
A=(15000)(0.032)(10)+15000
A=4800+15000
A=19800
Simple interst pays $19,800 in 10 years
Option B: compound interest
for interest compounded yearly, the formula is

where A=final amount
P=principal
r=rate in decimal form
t=time in years
given
P=15000
r=4.1% or 0.041
t=10


use your calculator
A=22418.0872024
so after 10 years, she will have $22,418.09 in the compounded interest account
in 10 years, the investment in the simple interest account will be worth $19,800 and the investment in the compounded interest account will be worth$22,418.09
Answer:
Step-by-step explanation:
X=-6