Neither a relation nor a function because their a negative 3
and that's a non function
A) For both sets A and B, calculating the mean, range, and quartiles are a good way of measuring the center and spread. Using standard deviation may not be the best because we do not know whether the distributions are normal or not.
b) For set A, the lowest value is 63, while the highest is 86. An estimate for the mean, based on the average of these, is 74.5. Most of the 70+ values are below 74.5, so we may guess that the mean will be above the median.
For set B, the lowest is 63, while the maximum is 95. The estimated mean would be 79. But since there are more values on the 80+ and 90+ side, the median is likely to be higher than 79.
c) For set A, the mean is 74.79, while the median is 73, therefore the mean is above the median, and the prediction in part b is correct.
Answer:
area of the figure=(2×5)+(6×2)
=10+12
=22
9. Square
10. Square
11. Rectangle
12. Rectangle
13. Square
14. Triangle
Explanation:
I think you may have confused parallel and perpendicular for some of the questions. Also, a cube has square sides and base, so any crossection parallel or perpendicular will also be square. I hope this is helpful!
Answer:
The maximum value is 3.
Step-by-step explanation:
The given trigonometric function is

The amplitude of this function is 5.


The function is shifted vertically down by two units.
To find the maximum value, we add -2 to the upper boundary of A.
The maximum values is 5-2=3