X2 + 6x + y2 + 6y + 2 = 0
1 answer:
You might be interested in
Complete Question:
Find both the vector equation and the parametric equations of the line through (0,0,0) that is perpendicular to both and
where t = 0 corresponds to the first given point.
Answer:
Vector equation: (x, y, z) = (0, 0, 0) + t ( u x w)
Parametric equation:
x = -2t
y = -4t
z = 2t
Step-by-step explanation:
Since the line is perpendicular to and
, we will find the cross product of u and w
The equation of the line can be given by:
(x, y, z) = (0, 0, 0) + t ( u x w)
(x, y, z) = (0, 0, 0) + t < -2, -4, 2 >
x = -2t, y = -4t, z = 2t