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STALIN [3.7K]
4 years ago
15

The vertex of the graph of y = -4(x + 3)2 + 2 is​

Mathematics
1 answer:
Fantom [35]4 years ago
3 0

Answer:

vertex = (- 3, 2 )

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

y = - 4(x + 3)² + 2 ← is in vertex form

with (h, k ) = (- 3, 2 )

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8. Find the other endpoint of the segment with a midpoint of (-6, 4) and endpoint of (4, 8).
sukhopar [10]

Answer:

1,3 is the answer... if you look down here↓:

Step-by-step explanation:

4 0
2 years ago
Pull displays his sports trophies on shelves in his room. he has 5 trophies on each of 3 shelves and 2 trophies on another shelf
Vesnalui [34]
5 + 5 + 5 = 15
15 + 2 = 17 trophies
(5 x 3) + 2 = x (This is a possible way of writing the expression.)
5 0
3 years ago
Is this correct and if not can you please help me?
frozen [14]

Answer:

No problems here!

Great Job!

Step-by-step explanation:

4 0
3 years ago
Please help.
kati45 [8]
-9 < 6 -v < 9 . . . . two inequalities
-15 < -v < 3 . . . . . subtract 6
-3 < v < 15 . . . . . . multiply by -1

6 0
3 years ago
Twenty identical looking packets of white power are such that 15 contain cocaine and 5 do not. Four packets were randomly select
xxMikexx [17]

Answer:

The probability of selecting randomly 6 packets such that the first 4 contain cocaine and 2 not is 0.3522.

Step-by-step explanation:

Probabilities of selecting 4 packets with the ilegal substance:

(\frac{15}{4})\\= \frac{15!}{4!(15-4)!}

Combinassions possible= 1365

Probabilities of selecting 2 packets with white powder:

(\frac{5}{2})= \frac{5!}{2!(5-2)!}

Combinations possible= 10

Probabilities of selecting 6 packets from the totality of them:

(\frac{20}{6}) = \frac{20!}{6!(20-6)!}

Combinations possible= 38760

The probability of picking 4 with the substance and 2 with only white powder is:

\frac{(15ncr4)(5ncr2)}{(20ncr6)} = 0.3522

I hope this answer helps you.

6 0
3 years ago
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