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3 years ago

Help me fast please ASAP

Mathematics

2 answers:

Bond [772]3 years ago

8 0

Answer:

see explanation

Step-by-step explanation:

(a)

Record the number of sticks and look for a pattern

1 → 6 sticks

2 → 10 sticks

3 → 14 sticks

There is a difference of + 4 between each pattern, thus add 4 to the previous pattern , that is

4 → 14 + 4 = 18

5 → 18 + 4 = 22

6 → 22 + 4 = 26

That is there are 26 sticks in pattern number 6

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(b)

Multiplying the pattern number (n) by the difference 4 gives

4 × 1 = 4 ← require to + 2 for 6

4 × 2 = 8 ← require to + 2 for 10

4 × 3 = 12 ← require to + 2 for 14

Thus pattern number n would have

sticks = 4n + 2

krok68 [10]3 years ago

7 0

Answer:

6 sticks for the pattern of number 6

3 sticks for the pattern of number n

Step-by-step explanation:

Please check the attached picture.

This is a standard way to create number 6 and number n from sticks.

Hope this helps!

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Answer:

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Step-by-step explanation:

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3 years ago

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One fourth dived by one fourth

viva [34]

1; (1/4)/(1/4), all you do is flip the fraction to make the reciprocal and multiply, so (4/1)x(1/4)=1

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4 years ago

Please help with right answers xoxo

ludmilkaskok [199]

Y = 3x - 4

y = 3(-1) - 4
y = -3 - 4 = -7
Graph pair is (-1, -7)

y = 3(0) - 4
y = 0 - 4 = -4
Graph pair is (0, -4)

y = 3(2) - 4
y = 6 - 4 = 2
Graph pair is (2, 2)

y = 3(4) - 4
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Graph pair is (4, 8)

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3 years ago

Simplify the square root of 40x^4

Otrada [13]

Answer:

4 = 22

Step-by-step explanation:

Factor 40 into its prime factors

40 = 23 • 5

To simplify a square root, we extract factors which are squares, i.e., factors that are raised to an even exponent.

Factors which will be extracted are :

4 = 22

Factors which will remain inside the root are :

10 = 2 • 5

To complete this part of the simplification we take the squre root of the factors which are to be extracted. We do this by dividing their exponents by 2 :

2 = 2

At the end of this step the partly simplified SQRT looks like this:

2 • sqrt (10x4)

Rules for simplifing variables which may be raised to a power:

(1) variables with no exponent stay inside the radical

(2) variables raised to power 1 or (-1) stay inside the radical

(3) variables raised to an even exponent: Half the exponent taken out, nothing remains inside the radical. examples:

(3.1) sqrt(x8)=x4

(3.2) sqrt(x-6)=x-3

(4) variables raised to an odd exponent which is >2 or <(-2) , examples:

(4.1) sqrt(x5)=x2•sqrt(x)

(4.2) sqrt(x-7)=x-3•sqrt(x-1)

Applying these rules to our case we find out that

SQRT(x4) = x2

sqrt (40x4) =

2 x2 • sqrt(10)

Simplified Root :

2 x2 • sqrt(10)

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2 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Oduvanchick [21]

Answer:

see attached

Step-by-step explanation:

The Pythagorean theorem can be used to find the hypotenuse associated with each pair of legs. That tells you ...

c² = a² +b² . . . . . legs a, b; hypotenuse c

<h3>alternate form of Pythagorean theorem</h3>

For the purpose of this problem, it is convenient to consider a slightly different form of the equation.

For legs √a and √b, the hypotenuse √c is given by ...

(√c)² = (√a)² +(√b)²

c = a +b

That is ...

legs √a, √b ⇒ hypotenuse √(a+b)

<h3>application to this problem</h3>

Since the legs are (mostly) given in terms of square roots, the value under the radical for the hypotenuse is simply the sum of those:

legs: √1, √2 ⇒ hypotenuse √(1+2) = √3

legs: √2, √3 ⇒ hypotenuse √(2+3) = √5

legs: √5, √3 ⇒ hypotenuse √(5+3) = √8

legs: √5, √1 ⇒ hypotenuse √(5+1) = √6

_____

<em>Additional comment</em>

You may not see the leg lengths given as square roots very often. This is a rather unusual set of problems for hypotenuse length.

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2 years ago

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