Answer:
Step-by-step explanation:
First we need the find the set of x such as 2x + 3 >= -3
2x + 3 >= -3 [Sum -3 in both sides]
2x + 3 - 3 >= - 3 - 3
2x >= -6 [Now, divide both sides by 2]
2x / 2 >= -6/2
x >= - 3
So, for every x>= -3 we have that 2x + 3 >= -3
Now we do the same with the other ineq:
5x-2 < 3 [sum 2 in both sides]
5x - 2 + 2 < 3 + 2
5x < 5 [divide by 5 in both sides]
5x / 5 < 5 / 5
x < 1
So, for every x<1 we have 5x-2<3
Then our set it the intersection of both of the previous sects, it is:
(x<1)intersect(x>=-3):
Solution: -3 =< x < 1
Answer:
my answer is 17 5/5
Step-by-step explanation: so what i did was that i add 13 and 4/5 but i can't add like that so i put 13/1 + 4/5 and they don't have the same denominator so i did 1 x 5 so if i do it on the bottom i have to do it on the top and so i did 13 x 5 and 13 x 5 is 65 and 1 x 5 is 5 and so my new fractions are 65/5 + 4/5 and i add both them and got 69/5 so i divided 69 and 5 and got 13 4/5 and then i add 69/5 plus 4 and turn the 4 into 4/1 and multiply 1 x 5 and have to do it on the top so 4 x 5 and got 20/5 and now add 69/5 + 20/5 and got 89/5 as my answer and divided 89 divided by 5 and got 17 5/5 and know it that is my answer.
hope it helps you!
The number of cookies packs needed if the treasurer buys 1 package of brownies bites is 5 packs
<h3>Equation</h3>
- Total attendance = 75 people
- Cookies in each pack = 12
- Brownies in each pack = 15
- Number of cookies pack = c
- Number of brownies pack = b
15b + 12c = 75
If 1 package of brownies is bought
15b + 12c = 75
15(1) + 12c = 75
15 + 12c = 75
12c = 75 - 15
12c = 60
c = 60/12
c = 5 packs
- It is a reasonable value in this context
If 9 packages of brownies are bought
15b + 12c = 75
15(9) + 12c = 75
135 + 12c = 75
12c = 75 - 135
12c = -60
c = -60/12
c = -5 packs
- The value is not reasonable in this context
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5xy=10
xy=10/5
xy= 2
this might not be the same topic im thinking about