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Assoli18 [71]
3 years ago
10

the price of a stock decreasing rupees 45 per day for the four constitutive days. what was the total change in value of the stoc

k over 4 days period?​
Mathematics
1 answer:
Simora [160]3 years ago
4 0

Hi,

45 per day

4 day period

45 * 4 = 180

180 rupees

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I’m honestly confused on how to solve for k. please help.
stellarik [79]

Answer:

k=9

Step-by-step explanation:

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1 year ago
Find the slope of the graph
artcher [175]
2/3 (i’m not amazing at slope but i believe it is 2/3)
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3 years ago
Evaluate. Show all work<br> 51-(21-5)x2
masya89 [10]

Answer:

19

Step-by-step explanation:

51-(16)x2

16x2=32

51-32=19

5 0
2 years ago
Read 2 more answers
Find an exact value cos(19pi/12)
dmitriy555 [2]

cos\left ( \frac{9\pi}{12}\right )=\frac{\sqrt{2-\sqrt{3}}}{2}

Step-by-step explanation:

We know that

          cos 2x = 2cos²x - 1

So we have

          cosx=\sqrt{\frac{1+cos2x}{2}}

Substituting x=\frac{19\pi}{12}

         cos\left ( \frac{19\pi}{12}\right )=\sqrt{\frac{1+cos2\left ( \frac{19\pi}{12}\right )}{2}}\\\\cos\left ( \frac{19\pi}{12}\right )=\sqrt{\frac{1+cos\left ( \frac{19\pi}{6}\right )}{2}}\\\\cos\left ( \frac{9\pi}{12}\right )=\sqrt{\frac{1+cos570}{2}}\\\\cos\left ( \frac{9\pi}{12}\right )=\sqrt{\frac{1-\frac{\sqrt{3}}{2}}{2}}\\\\cos\left ( \frac{9\pi}{12}\right )=\sqrt{\frac{2-\sqrt{3}}{4}}\\\\cos\left ( \frac{9\pi}{12}\right )=\frac{\sqrt{2-\sqrt{3}}}{2}

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3 0
2 years ago
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Laura shades 60 squares on her hundredths grid And Billy shades 50 squares on his hundredths grid. Write the decimal number that
Andre45 [30]

Answer:

Laura = 0.60

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Step-by-step explanation:

Given

Laura = 60\ shades

Billy = 50\ shades

Required

Represent using decimal number and compare

From the question, we understand that there are 100th grids;

So:

Laura = \frac{60}{100}

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Comparing both decimals;

Since 0.60 is greater than 0.50, we have:

0.60 > 0.50

3 0
3 years ago
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