Answer:
rom the relation for linear regression formula, Y = b·X + a, we have ;
For car 1
ΣXY = 102780
(ΣX)² = 36
ΣX = 6
ΣY = 52390
ΣX² = 14
N = 3
b = -1000
a = 19463
Y = -1000×X + 19463
For Car 2
ΣXY = 102539.8
(ΣX)² = 36
ΣX = 6
ΣY = 52346.6
ΣX² = 14
N = 3 .
b = -1076.7
a = 19602
Y = -1076.7×X + 19602
Step-by-step explanation:
part B ^
Clue one tells you it ends in a 4 or 9.
Clue two tells you it has to be 9.
Clue three tells you x + 9 = 10
The number is 19
The value of the fractions will be:
1. 8 13/20
2. 2 4/5
3. 5/6
<h3>How to explain the fraction?</h3>
1. 6 1/4 + 2 2/5
LCM of 20
6 1/4 + 2 2/5.
6 5/20 + 2 8/20
= 8 13/20
2. 1 1/5 × 2 1/3
= 6/5 × 7/3
= 42/15
= 14/5
= 2 4/5
3. 3 1/3 - 2 1/2
= 3 2/6 - 2 3/6.
= 5/6
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There is one solution. The solution of the system is (9,-5)
Option A is correct.
Step-by-step explanation:
We need to solve the system of equations by elimination method
![6x= 64+2y\\2x= -7-5y](https://tex.z-dn.net/?f=6x%3D%2064%2B2y%5C%5C2x%3D%20-7-5y)
Rearranging the equations:
![6x-2y=64\,\,\,eq(1)\\2x+5y=-7\,\,\,eq(2)](https://tex.z-dn.net/?f=6x-2y%3D64%5C%2C%5C%2C%5C%2Ceq%281%29%5C%5C2x%2B5y%3D-7%5C%2C%5C%2C%5C%2Ceq%282%29)
Eliminating y to find value of x:
Multiply eq(1) by 5 and eq(2) by 2 and add both equations:
![30x-10y=320\,\,\,\\4x+10y=-14\\--------\\34x=306\\x=\frac{306}{34}\\ x=9](https://tex.z-dn.net/?f=30x-10y%3D320%5C%2C%5C%2C%5C%2C%5C%5C4x%2B10y%3D-14%5C%5C--------%5C%5C34x%3D306%5C%5Cx%3D%5Cfrac%7B306%7D%7B34%7D%5C%5C%20x%3D9)
So, value of x= 9
Eliminating x to find value of y:
Multiply eq(1) by 2 and eq(2) by 6 and subtract both equations:
![12x-4y=128\\12x+30y=-42\\-\,\,\,\,-\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+\\---------\\-34y=170\\y=\frac{170}{-34}\\ y=-5](https://tex.z-dn.net/?f=12x-4y%3D128%5C%5C12x%2B30y%3D-42%5C%5C-%5C%2C%5C%2C%5C%2C%5C%2C-%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%5C%2C%2B%5C%5C---------%5C%5C-34y%3D170%5C%5Cy%3D%5Cfrac%7B170%7D%7B-34%7D%5C%5C%20y%3D-5)
So, value of y = -5
There is one solution. The solution of the system is (9,-5)
Option A is correct.
Keywords: Solving system of equations
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Answer:
3/5 has the smallest denominator
Step-by-step explanation:
Question:
There exist infinitely many common fractions a/b , where a > 0 and b > 0 and for which 3/5 < a/b< 2/3. Of these common fractions, which has the smallest denominator? Express your answer as a common fraction.
Solution
A Common fraction is a rational number written in the form: a/b. Where a and b are both integers.
The denominator and numerator in this case are greater than zero. That is, they are non zeros.
The least common denominator (LCD) of two non- zero denominators is the smallest whole number that is divisible by each of the denominators.
To find the smallest denominator between 3/5 and 2/3, we would convert the fractions to equivalent fractions with a common denominator by finding their LCM (lowest common multiple).
When comparing two fractions with like denominators, the larger fraction is the one with the greater numerator and the smaller fraction is one with the smaller numerator.
In our solution after comparing, the smaller fraction would have the smallest denominator.
Find attached the solution.