On a hot day, a football team drank an entire 50-gallon cooler of water and half as much again. How much water did they drink?

Mathematics

2 answers:

NemiM [27]3 years ago

7 0

Answer:

The football team drank a total of 75 gallons of water.

Step-by-step explanation:

Half of 50 gallons is 25 gallons. 25 gallons + 50 gallons = 75 gallons.

GrogVix [38]3 years ago

5 0

Answer:

They drank 75 gallons of water.

Step-by-step explanation:

We know that the entire cooler of water can be filled with 50-gallon of water.

We know that the football team drank an entire cooler and half as much again.

If ''V'' is the volume of the cooler we can write this mathematically as :

$V+\frac{1}{2}V=V+(0.5)V=(1.5)V$

The equation expresses that the team drank 1.5 times the total capacity of the cooler ⇒ Multiplying 1.5 by the total capacity of the cooler we will obtain the total gallons of water that the football team drank :

$(1.5)(50Gallons)=75Gallons$

The football team drank 75 gallons of water.

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I need help on this.

mote1985 [20]

Let's go:

7 = x

38 + x = 180

x = 180 - 38

x = 142°

7 = 142°

I hope I helped you

5 0

3 years ago

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NeTakaya

Answer:

For this case a parameter represent the population data and for this case the parameter would be the true mean $\mu$ who represent the amount of gasoline they used in the previous week

$\bar X= \frac{\sum_{i=1}^n X_i}{3800} =11.75$

And the sample mean is an unbiased estimator of the true mean.

Step-by-step explanation:

For this case a parameter represent the population data and for this case the parameter would be the true mean $\mu$ who represent the amount of gasoline they used in the previous week

And in order to estimate the parameter of interest we use a survey of n =3800 and the sample mean who represent an statistic is given by:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$