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3 years ago

On a hot day, a football team drank an entire 50-gallon cooler of water and half as much again. How much water did they drink?

Mathematics

2 answers:

NemiM [27]3 years ago

7 0

Answer:

The football team drank a total of 75 gallons of water.

Step-by-step explanation:

Half of 50 gallons is 25 gallons. 25 gallons + 50 gallons = 75 gallons.

GrogVix [38]3 years ago

5 0

Answer:

They drank 75 gallons of water.

Step-by-step explanation:

We know that the entire cooler of water can be filled with 50-gallon of water.

We know that the football team drank an entire cooler and half as much again.

If ''V'' is the volume of the cooler we can write this mathematically as :

$V+\frac{1}{2}V=V+(0.5)V=(1.5)V$

The equation expresses that the team drank 1.5 times the total capacity of the cooler ⇒ Multiplying 1.5 by the total capacity of the cooler we will obtain the total gallons of water that the football team drank :

$(1.5)(50Gallons)=75Gallons$

The football team drank 75 gallons of water.

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c
, we need to think of 2 numbers such that:
N
1
⋅
N
2
=
a
⋅
c
=
3
⋅
3
=
9

and,
N
1
+
N
2
=
b
=
10
After trying out a few numbers we get:
N
1
=
9
and
N
2
=
1

9
⋅
1
=
9
, and
9
+
(
1
)
=
10
3
x
2
+
10
x
+
3
=
3
x
2
+
9
x
+
1
x
+
3

=
3
x
(
x
+
3
)
+
1
(
x
+
3
)
(
3
x
+
1
)
(
x
+
3
)
is the factorised form for the expression.

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