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ELEN [110]
2 years ago
12

if Roman Reigns was born 759 days after Jey Uso, with no leap year between the two birthdays. If Jey Uso was born on a Wednesday

, on what day of the week was Roman Reigns born?
Mathematics
1 answer:
sweet-ann [11.9K]2 years ago
4 0

If Jey Uso was  born on a Wednesday, the day of the week that  Roman Reigns was born is Thursday.

<h3>What day of the week was  Roman Reigns born?</h3>

There are 365 days in a year when there is no leap year.

Now determine the number of years that make up 759 days: 759 / 365 = 2 years + 29 days

Now determine how many weeks are in 29 days : 29 / 7 = 4 weeks and 1 day

Thus,  Roman Reigns was born on Thursday.

To learn more about division, please check: brainly.com/question/194007

#SPJ1

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Solve for x. Evaluate and round your answer to 1 decimal place(tenths place). 10x=1200
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Answer:

<h2>x = 3.1</h2>

Step-by-step explanation:

<h3>{10}^{x}  = 1200</h3>

<u>To solve first take logarithm to both sides</u>

That's

<h3>log_{10}(10) ^{x}  =  log_{10}(1200)</h3><h3 /><h3>log_{10}(10)^{x}  = x log_{10}(10)</h3>

But

<h3>log_{10}(10)  = 1</h3>

So we have

x =  log_{10}(1200)

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1200 = 100 × 12

So we have

<h3>x =  log_{10}(100 \times 12)</h3>

<u>Using the rules of logarithms</u>

That's

<h3>log_{a}(x \times y)  =  log_{a}(x)  +  log_{a}(y)</h3>

Rewrite the expression

That's

<h3>x =  log_{10}(100)  +  log_{10}(12)</h3><h3 /><h3>x =  log_{10}(10)^{2}  +  log_{10}(12)</h3><h3>x = 2 log_{10}(10)  +  log_{10}(12)</h3><h3>log_{10}(10)  = 1</h3><h3 /><h3>x = 2 +  log_{10}(12)</h3>

x = 3.079

So we have the final answer as

<h3>x = 3.1 to one decimal place</h3>

Hope this helps you

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