Complete the equation of the line whose slope is -2 and y intercept is (0,-8)

Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match the system of equations with their so

allochka39001 [22]

Answer:

Part 1) solution {(-5,8),(3,0)} ----> $y+12=x^{2}+x$ and $x+y=3$

Part 2) No solutions ----> $y-15=x^{2}+4x$ and $x-y=1$

Part 3) solution [(-2,5),(3,-5)] ---> $y+5=x^{2}-3x$ and $2x+y=1$

Part 4) No solutions ---> $y-6=x^{2}-3x$ and $x+2y=2$

Part 5) solution [(2,3),(8,9)] ---> $y-17=x^{2}-9x$ and $-x+y=1$

Part 6) solution [(-2,3),(7,-6)] ---> $y-15=-x^{2}+4x$ and $x+y=1$

Step-by-step explanation:

Part 1) we have

$y+12=x^{2}+x$ ----> equation A

$x+y=3$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-5,8) and (3,0)

see the attached figure N 1

Part 2) we have

$y-15=x^{2}+4x$ ----> equation A

$x-y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs

see the attached figure N 2

Part 3) we have

$y+5=x^{2}-3x$ ----> equation A

$2x+y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,5) and (3,-5)

see the attached figure N 3

Part 4) we have

$y-6=x^{2}-3x$ ----> equation A

$x+2y=2$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The system has no solutions, because there is no point of intersection between the two graphs

see the attached figure N 4

Part 5) we have

$y-17=x^{2}-9x$ ----> equation A

$-x+y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (2,3) and (8,9)

see the attached figure N 5

Part 6) we have

$y-15=-x^{2}+4x$ ----> equation A

$x+y=1$ ----> equation B

Solve by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution are the points (-2,3) and (7,-6)

see the attached figure N 6

5 0

3 years ago

A hose with a larger diameter working alone can fill a swimming pool in 9 hours.A hose with a smaller diameter working alone can

Arte-miy333 [17]

The large hose fills 1 pool in 9 hours written as 1/9

The small hose fills 1 pool in 18 hours, written as 1/18

Now you have 1/9 + 1/18 = 1/x ( x is the unknown time for both hoses).

rewrite 1/9 with a common denominator as 1/18:

1/9 = 2/18

Now you have 2/18 + 1/18 = 1/x

Add the left side:

2/18 + 1/18 = 3/18

Now you have 3/18 = 1/x

Cross Multiply:

3x = 18

Divide both sides by 3"

x = 18/3

X = 6

It will take both hoses 6 hours.

8 0

4 years ago

Find a recurrence relation for the amount of money in a savings account after n years if the interest rate is 6 percent and $50

Korvikt [17]

Answer:

$a_n = a_{n-1} (1.06) + 50$

Step-by-step explanation:

Suppose, $a_0$ is initial amount in the saving account,

Here, the annual interest rate is 6% and additional amount in each year is $ 50,

So, the amount after one year,

$a_1 = a_0 + 6\%\text{ of }a_0 + 50 = a_0 + 0.06a_0 + 50 = a_0(1.06) + 50$

Amount after 2 years,

$a_2 = a_1 + 6\%\text{ of }a_1 + 50 = a_1(1.06) + 50$

Amount after 3 years,

$a_3 = a_2 + 6\%\text{ of }a_2 + 50 = a_2(1.06) + 50$

................................., so on....

Hence, by following the pattern,

The amount after n years,

$a_n = a_{n-1} (1.06) + 50$

Which is the required recurrence relation for the amount of money in a savings account

3 0

4 years ago

What is the value of x in the equation 58 = 10x − 2?

solong [7]

Answer:

6

Step-by-step explanation:

10x6=60-2=58

7 0

3 years ago

Read 2 more answers

SOMEONE PLEASEEEE HELPPPP?!?!?!?!!?

Zarrin [17]

Answer:

Step-by-step explanation:

Top/Bottom = 12

Sides = 15

Front/Back = 20

20 + 15 + 12 = 47

47 / 1/2 = 23.5

8 0

3 years ago