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tensa zangetsu [6.8K]
3 years ago
5

Complete the equation of the line whose slope is -2 and y intercept is (0,-8)

Mathematics
1 answer:
Zepler [3.9K]3 years ago
4 0

Answer:

y=-2x-8

Step-by-step explanation:

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How to solve this problem?
SOVA2 [1]
Covert to a common denominator to help:
A LCD is 24.
12/24, 20/24, and 15/24

So 12/24, 15/24, 20/24
Convert back into their original denominators:
1/2, 5/8, 5/6.
F. 
6 0
3 years ago
Simplify.
inn [45]

Answer:

1. \frac{3y - 2}{5}    =  \frac{3y}{5} -  \frac{2}{5}    \\  \\ 2.    \frac{6x - 3}{3}  =  \frac{6x}{3}  -  \frac{3}{3}  \\ =  2x - 1 \\  \\ 3. \frac{4}{2}  = 2

8 0
2 years ago
10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the
Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

H_0: \mu = 0

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

H_1: \mu > 0

<h3>What is the test statistic?</h3>

The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

In this problem, the parameters are given as follows:

\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50.

Hence, the test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by t^{\ast} = 2.4.

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

5 0
2 years ago
There are a total of 15 dimes and quarters in a covered cup. The value of all 15 coins totals 2.85
QveST [7]

Answer:

There are 6 dimes and 9 quarters.

Step-by-step explanation:

Represent the number of dimes and the number of quarters by d and q.

Then d + q = 15, or q = 15 - d.

Also, ($0.25)q + ($0.10)d = $2.85, or 5q + 2d = 57.

Substituding 15 - d for q, we get 5(15 - d) + 2d = 57, or

75 - 5d + 2d = 57, or

75 - 3d = 57, or

3d = 18.  Thus, there are 6 dimes.  Since q = 15 - d, q = 15 - 6 = 9.

There are 6 dimes and 9 quarters.

6 0
3 years ago
Find the general solution of the given differential equation. cos^2(x)sin(x)dy/dx+(cos^3(x))y=1 g
eimsori [14]

If the given differential equation is

\cos^2(x) \sin(x) \dfrac{dy}{dx} + \cos^3(x) y = 1

then multiply both sides by \frac1{\cos^2(x)} :

\sin(x) \dfrac{dy}{dx} + \cos(x) y = \sec^2(x)

The left side is the derivative of a product,

\dfrac{d}{dx}\left[\sin(x)y\right] = \sec^2(x)

Integrate both sides with respect to x, recalling that \frac{d}{dx}\tan(x) = \sec^2(x) :

\displaystyle \int \frac{d}{dx}\left[\sin(x)y\right] \, dx = \int \sec^2(x) \, dx

\sin(x) y = \tan(x) + C

Solve for y :

\boxed{y = \sec(x) + C \csc(x)}which follows from [tex]\tan(x)=\frac{\sin(x)}{\cos(x)}.

7 0
2 years ago
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