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2 years ago

Given the triangle below, find the length of ZY. round your answer to the nearest tenth

Mathematics

1 answer:

anastassius [24]2 years ago

6 0

I can’t see the picture it’s blurry

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Factor x2 – 19x – 20 completely.

Naddik [55]

Answer:

Step-by-step explanation:

x^2-19x-20

=x^2-(20-1)x-20

=x^2-20x+x-20

=x(x-20)+1(x-20)

=(x-20)(x+1)

6 0

3 years ago

ambers starting salary with her new job will be 35,000 a year how much will she pay to the social security system for her first

anyanavicka [17]

I think it is 420,000

7 0

4 years ago

Read 2 more answers

Help!!!

german

Answer:

625 cm3

Step-by-step explanation:

Formula V1 * P1 = V2 * P2

V1 = 450 cm3

P1 = 125 kPa

P2 = 90 kPa

V2 = ?

V2 = (V1 * P1) / P2

V2 = (450 cm3 * 125 kPa) / 90 kPa = 625 cm3

4 0

4 years ago

What is x+8=(-5) and how do expan it

aalyn [17]

Answer:

X= -13

Step-by-step explanation:

The goal is to get x by itself!

Rule of thumb: whatever you do to the left, you MUST do to the right

Step 1: Subtract 8 from the left side of the equation (the = sign)

x + 8 = (-5)

- 8 --> this gets x by itself

Step 2: Subtract 8 from (-5) on the right side (because you did it on the left

x = (-5)

- 8

*note: x is now by itself*

Step 3: Solve!

x = (-5) - 8 -13

x = -13

8 0

4 years ago

A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f

tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

= 180° - (45° + 120°)

= 180° - 165°

= 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

$\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}$

$\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}$

$\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}$

PR = $\frac{12\text{sin}(120)}{\text{sin}(15)}$

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0

3 years ago