Solve by substitution<br><br> 8x+y=-16<br> -3x+ y= -5

2/7 divided by 1/4 =

dem82 [27]

Answer: 8/7

Step-by-step explanation:

To solve 2/7 ÷ 1/4,

Step 1: rewrite as-

2/7 × 4/1

=8/7

I hope this is clear.

4 0

3 years ago

Which phrase should be inserted on the line to correctly compare the two fractions? Use the models to help. StartFraction 7 Over

ANEK [815]

Answer:

7/8 is greater than 2/4

Step-by-step explanation:

In this question basically, what we are trying to do is to compare fractions and state which is greater or less.

The first fractions in the question is;

7/8 _ 2/4

Now, one of the best ways to go around comparing fractions is looking at the denominators.

In this question, the denominators in the fractions are 8 and 4.

The next thing to do here is to multiply the numerator and the denominator of the first by 4 and the numerator and the denominator of the second by 8. This makes it possible for us to have the same denominator in both fractions and thus compare both fractions directly.

Thus, what we have would be;

7/8 = 7/8 * 1 = 7/8 * 4/4 = 28/32

Now for the fraction;

2/4 = 2/4 * 1 = 2/4 * 8/8 = 16/32

We can see they both have a common denominator and we can directly compare their numerators.

Obviously, 28 is greater than 16 and this makes a case for the fact that 7/8 is greater than 2/4

So what we have in the blank is ; is greater than

Kindly note that the other part of the question that talks about shading circles is same as saying 7/8 and 2/4

5 0

3 years ago

Read 2 more answers

A computer program contains one error. In order to find the error, we split the program into 6 blocks and test two of them, sele

Aleksandr-060686 [28]

There are $\dbinom62$ ways of selecting two of the six blocks at random. The probability that one of them contains an error is

$\dfrac{\dbinom11\dbinom51}{\dbinom62}=\dfrac5{15}=\dfrac13$

So $X$ has probability mass function

$f_X(x)=\begin{cases}\dfrac13&\text{for }x=1\\\\\dfrac23&\text{for }x=0\end{cases}$

These are the only two cases since there is only one error known to exist in the code; any two blocks of code chosen at random must either contain the error or not.

The expected value of finding an error is then

$\displaystyle\sum_{x=0}^1xf_X(x)=0\times\dfrac23+1\times\dfrac13=\dfrac13$