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3 years ago

I need help on this. Plz help me

Mathematics

1 answer:

Brut [27]3 years ago

3 0

Just take the answer of the subtraction problem and add it to the other number for an answer Example h-7=14 14 + 7=21 h=7

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What is the value of the expression 2.6 x 10 to the power of 9 divided by 1.3 x 10 to the power of 2

bazaltina [42]

(2.6 * 10^9) / (1.3 * 10^2) =
(2.6 / 1.3) * (10^9) / (10^2) =
2 * 10^7 or 20,000,000 <===

7 0

3 years ago

An observer stationed 20 m away from a tall

antiseptic1488 [7]

Answer:

Step-by-step explanation:I don't say you must have to mark my ans as brainliest but my friend if it has really helped you plz don't forget to thank me...

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3 years ago

Read 2 more answers

Solve by taking the square root I need help understanding steps this is hard for me.

Shalnov [3]

Answer:

x= $-2 \pm \sqrt{13}$

Step-by-step explanation:

Given: $3x^{2} -12x+27= 0$

This is a quadratic equation.

$3x^{2} -12x+27= 0$

Taking common 3 from the equation given

⇒ $3(x^{2} -4x+9)=0$

dividing both side by 3

⇒ $x^{2} -4x+9=0$

By using different factor, we can observe this trinomial can not be factored.

∴ solving it by completing the square.

⇒ $x^{2} -4x+9=0$

adding 9 on both side

⇒ $x^{2} -4x= 9$

To get a perfect square number as coeffecient of x is 4, lets add both side by 4.

⇒ $x^{2} -4x+4= 13$

we know, $(x+2)^{2} = x^{2} +2\times x\times 2+2^{2}$

∴ $(x+2)^{2} =13$

Taking Square root on both side, remember; √a²= a

⇒ $(x+2)= \sqrt{13}$

opening parenthesis

⇒ $x+2= \sqrt{13}$

subtracting both side by 2

∴ x= $-2 \pm \sqrt{13}$

7 0

3 years ago

Helpppppppppppppppppppppppppppppppppppp

natulia [17]

Answer:

Each one is for 1.25 or around that if thats what youre asking I cant see it too well but if its correct you're welcome

Step-by-step explanation:

7 0

2 years ago

Don’t know how to solve

VladimirAG [237]

Answer:

(based on the given information) -21 - 8 = 31 + 10 = 41

Step-by-step explanation:

it's like adding 3 + 1, because there is nothing to add in the ones place

7 0

2 years ago