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3 years ago

7

4x+7y= 28 solve for y Not a graphing question

1 answer:

Nuetrik [128]3 years ago

4 0

The answer I got was y=-4/7x +4

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Six mini cakes and 10 cookies cost

Rus_ich [418]

A cookie costs 7 dollars and a mini cake costs 5 dollars

8 0

2 years ago

Read 2 more answers

A carpenter is assigned the job of expanding a rectangular deck where the width is one-fourth the length. the length of the deck

anzhelika [568]

Alright, lets get started.

Suppose the original deck size: width = x feet

the width is one-fourth the length given in question means length = 4 x feet

Means the originally area = $x * 4 x = 4 x^{2}$

Now the dimensions are changed.

New dimensions, width = (x + 6)

new length = (4x+10)

So, new area will be = $(x+6) * (4x+10) = 4x^{2} + 10 x + 24 x + 60 = 4x^{2} + 34 x + 60$

the area of the new rectangular deck is 128 ft2 larger than the area of the original deck, means

$4x^{2} + 128= 4x^{2} + 34 x + 60$

Subtracting $4x^{2}$ from both sides

$128 = 34 x + 60$

Subtracting 60 from both sides

$128 - 60 = 34 x + 60 - 60$

$68 = 34 x$

Dividing 34 in both sides

$\frac{68}{34} = \frac{34 x }{34}$

$x = 2$

Means width = 2 feet

Length would be = 4 time width = 4 * 2 = 8 feet

Means dimension of original deck would be = 2 feet and 8 feet :Answer

Hope it will help :)

8 0

3 years ago

Not homework BUT

Alborosie

Answer:

242 days

Step-by-step explanation:

1081-597=484

it is increasing by 2wins every day so 484/2=242 days

5 0

2 years ago

A rectangular piece of plywood has a diagonal which measures two feet more than the width. The length of the plywood is twice th

icang [17]

Answer:

The length of the plywood's diagonal(to the nearest tenth) is, 3.6 and 1.4

Step-by-step explanation:

let l be the length and w be the width of the rectangle respectively;

Diagonal(D) of a rectangle is given by:

$D = \sqrt{l^2+w^2}$ ......[1]

As per the given statement we have;

Diagonal(D) = width + 2

and

$l = 2 \times w$ = 2w

Now, substitute these in [1] we have;

$\sqrt{(2w)^2+w^2} = w+5$

Squaring both the sides we get;

$4w^2+w^2 = (w+2)^2$

$5w^2 = w^2 + 4 + 4w$

or

$5w^2 -w^2 = 4w + 4$ or

$4w^2= 4w + 4$

Simplify:

$w^2-w-1 =0$ ......[2]

The quadratic equation is in the form of $ax^2+bx+c = 0$

the solution is given by: $x = \frac{-b \pm\sqrt{b^2-4ac}}{2a}$

On comparing with [1] we get

a= 1 , b = -1 and c = -1

Then the solution is:

$w= \frac{-(-1) \pm\sqrt{(-1)^2-4(1)(-1)}}{2(1)}$

$w =\frac{1 \pm\sqrt{1+4}}{2} = \frac{1 \pm\sqrt{5}}{2}$

Simplify:

$w \approx 1.62$ and $w \approx -0.62$

Then, the diagonal D = w+2

For $w \approx 1.62$

$D = 1.62 +2 \approx 3.62$

For $w \approx -0.62$

$D =-0.62 +2 \approx 1.38$

therefore, the length of the plywood's diagonal(to the nearest tenth) is, 3.6 and 1.4

5 0

3 years ago

Bro what is going on here?

miv72 [106K]

Answer:

That's math for you.

Step-by-step explanation:

8 0

2 years ago