3 years ago

Uh hey I need help on this

1 answer:

8 0

Answer:

exactly one solution

I would appreciate if my answer is chosen as a brainliest answer

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Nastasia [14]

Answer: ($141,775, $158,225)

Step-by-step explanation:

Given : Significance level : $\alpha: 1-0.9=0.1$

Critical value : $z_{\alpha/2}=1.645$

Sample size : n= 49

Sample mean : $\overline{x}=150,000$

Standard deviation : $\sigma=35,000$

The confidence interval for population mean is given by :_

$\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

$= 150,000\pm (1.645)\dfrac{35000}{\sqrt{49}}\\\\\approx150,000\pm8225\\\\=(150,000-8225,150,000+8225)=(141,775,158,225)$

Hence,he 90% confidence interval for the average salary of a CFA charter-holder = ($141,775, $158,225)

7 0

3 years ago

Galina-37 [17]

B is maybe the answer not really sure

5 0

4 years ago

Vanyuwa [196]

Hope this will help u. If my ans was helpful u can follow me.

THANKYOU.

3 0

3 years ago

ElenaW [278]

Likely is your answer

7 0

3 years ago

n200080 [17]

2. Eliza - 17 years.
$8500 x 6.5% = $552.50 for 1 year
$9,392.50/ $552.50 = 17 years.

3 0

3 years ago