Answer:
The root mean square speed of O2 gas molecules is
<u>519.01 m/s</u>
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Explanation:
The root mean square velocity :
Molar mass , M
For He = 4 g/mol
For O2 = 2 x 16 = 32 g/mol
O2 = 32/1000 = 0.032 Kg/mol
First calculate the temperature at which the K.E of He is 4310J/mol
K.E of He =
K.E of He = 4310 J/mol
<u>Now , Use Vrms to calculate the velocity of O2</u>
Answer:
42.1 kj
Explanation:
Given data:
Molar heat of vaporization = 3.86×10⁴ j/mol
Mass of ethanol = 50 g
Amount of heat required to convert into gaseous form = ?
Solution:
First of all we will calculate the number of moles of ethanol.
Number of moles = mass/ molar mass
Number of moles = 50.0 g/ 46.07 g/mol
Number of moles = 1.09 mol
H(vap) = number of moles × molar heat of vaporization
H(vap) = 1.09 mol × 3.86×10⁴ j/mol
H(vap) = 4.21×10⁴ j
In Kj:
4.21×10⁴ / 1000 = 42.1 kj
Molar mass SiO2 = 28 + 32 = 60
<span>so moles sand = 3.4 x 10-7 / 60</span>
If you need help reading it then ask away, the two answers end up being, 2Na, and 2NO3
Remember that enzymes always accelerate chemical equations, depending on what the enzyme is consisted of. As the enzymes are burned the reaction or amount of chemical reactions decreases.
