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STatiana [176]
3 years ago
11

Which is a spectator ion in the reaction between Na2CO3(aq) and HNO3(aq)?

Chemistry
2 answers:
Lelechka [254]3 years ago
7 0

<u>Answer:</u> The spectator ions are NO_3^-\text{ and }Na^+

<u>Explanation:</u>

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:

Na_2CO_3+2HNO_3\rightarrow 2NaNO_3+H_2O+CO_2

The ionic equation for the above reaction follows:

2Na^+(aq.)+CO_3^{2-}(aq.)+2H^+(aq.)+2NO_3^-\rightarrow 2Na^+(aq.)+2NO_3^-(aq.)+CO_2(g)+H_2O(l)

The net ionic equation follows:

CO_3^{2-}(aq.)+2H^+(aq.)+\rightarrow CO_2(g)+H_2O(l)

The ions which are present on both the sides of the equation are sodium and nitrate ions.

Hence, the correct answer are NO_3^-\text{ and }Na^+

Korolek [52]3 years ago
6 0
If you need help reading it then ask away, the two answers end up being, 2Na, and 2NO3

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On a summer day, you take a road trip through Death Valley, California, in an antique car. You start out at a temperature of 21°
MrRissso [65]
<span>There is only one formula to use and we should assume ideal gas. This equation is: PV=nRT. For the following questions manipulate this equation to get the answer.
 1. n = PV/RT = (249*1000 Pa)(15.6 L)(1 m^3/1000 L)/(8.314 Pa-m^3/mol-K))(21+273) = 1.59 mol
 2. P = nRT/V = (1.59)(8.314)(51+273)/(15.6/1000)(1000) = 274.55 kPa
 3. Since the answer in #2 is more than 269 kPa, then the tires will likely burst. 4. Reduce pressure way below the limit 269 kPa.</span>
4 0
3 years ago
Sulfur dioxide emissions from coal-burning power plants are removed by flue-gas desulfurization. The flue gas passes through a s
irakobra [83]

So they tell us that we have four giggle years of flue gas and they're wanting us to find out how much calcium Sophia in kilograms we can obtain from this. So we know that one Giga Leader is equal to one time 10 to the nine leaders.

and they inform us that our stress is equal to one surroundings and that our temperature is equal to 25 degrees Celsius. i am just gonna add to seventy three Calvin to this. So our temperature goes to be 98. Calvin. All proper, so we are simply gonna plug the whole thing into our equation. So one atmosphere times our quantity so four times, 10 to the nine leaders. we're gonna divide this through ours. i'm just gonna use artwork zero.8 to 1 leader's atmosphere per mole, Kelvin.

and then we are gonna times that by way of our temperature. so to 98 Calvin. All right, so when we calculate this out, are moles of flue gasoline is gonna identical to one.6 35 instances generally tend to the 8 moles of our flue gasoline. So now that we've got our moles of flue gas, we need to find a connection between the most of flue fuel and the mass of our calcium selfie.

So if we pass up here, we see that one more of our silver dioxide is equal to at least one mole of our calcium sulfate. So we're gonna use that connection to help us discover the big calcium selfie. So we want to locate the moles of our sulfur dioxide and they provide us the mole fraction for silver dioxide. they say it's a thousand times that of clean air, and we recognize that the mole fraction for easy air is two instances 10 to the negative 10.

So our mole fraction to be able to is equal to two instances 10 to the poor, 10 times a thousand. So our new mole fraction for S 02 goes to be  instances 10 to the terrible seven. Hurry. And we realize our moles of sulfur dioxide are identical to its mole fraction times the full wide variety of moles. So we do recognise the full variety of moles.

it's what number of moles of our flue gas we have. So our moles of eso to is gonna be too  instances 10 to the negative seven instances 1.635 times tend to the 8 moles. So our moles of sulfur dioxide goes to be 32.7 moulds. So now that we've maximum of the sulfur dioxide, we are able to get the moles of our calcium, Sophie, and that's just gonna be the moles of our sulfur dioxide. And we're gonna times that by means of that one toe, one-mole ratio. So one mole, calcium Sophie to at least one-mole sulfur dioxide.

So the moles of our calcium sulphate is the same at 32.7 maximum. So now, to get the mass of our calcium selfie, we simply take our range of maximum of 32.7 moles. I worked inside the times that via its molar mass, that's 136.14 grams in keeping with mole.

So our mass of calcium sulfate is equal to four hundred or 4451.eight g. They need this in kilograms. Sword goes to divide this by way of hundreds. So when we do this, it is gonna equal 4 factors for 518 kilograms of our calcium. So toes and that is Thea amount or the mass of calcium sulphate we will get from four Giga leaders of flue gasoline.

All right, so for the second a part of this question, they're asking us the quantity of air needed to react with all the calcium sulphides. as a way to figure that out, we're gonna need to parent out the moles of 02 They do give us the mole fraction for 02 and it is identical to 0.2 09 after which we're searching out the quantity of air in leaders. All proper, so we recognize that moles of 02 are identical to its small fraction times the full moles of air So maximum of 02 is gonna be 0 factor 209 times all through moles of air.

So allow's simply use that variety for our Mueller ratio to discern out our moles of calcium sulphate. So we are gonna use 32.7 of our calcium, so fight as it's simply gonna be a 1 to one ratio. Oh, we recognize that for each 1.five moles of 02 we've one mole, our calcium sulfate. and then we also know that for each one mole of air, we've got zero.209 moles of 02 So we calculate this out. Are moles of air goes to same 78.2 moles of air?

So then, to get the volume we are simply gonna use PV is same to N. R. T. So we're solving for quantity. So n r t divided through the pressure. They tell us that the pressure is same to 1 environment and we are gonna be using a temperature equal to 2 98 Calvin.

So our extent is gonna identical 78.2 moles of air while times that through our cost of zero.8 to one leaders surroundings in keeping with greater Calvin or in times that fireplace temperature, which is to ninety eight Calvin, I might not divide all of this through one surroundings. So our extent of air is gonna identical to 1913 leaders of air this is had to react absolutely with calcium sulfate. and that's how we noticed the second part of this problem.

Learn more about calcium sulfate brainly.com/question/7962933

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6 0
1 year ago
Consider the following exothermic reaction and predict how the change below will affect the concentration (increase, decrease, s
aev [14]

Answer:

a) equilibrium shifts towards the left

b) equilibrium shifts towards the right hand side.

c)equilibrium shifts towards the left hand side

d) addition of argon has no effect on the equilibrium position

e) equilibrium position shifts towards the left hand side

f) equilibrium position is shifted towards the right hand side

g) addition of a catalyst has no effect on the equilibrium position

Explanation:

Given the equation;

3N2H4(g)⇄ 4NH3 (g) + N2 (g)

Adding N2

The addition of N2 will increase the concentration of N2 in the system thereby shifting the equilibrium position to the left in accordance with Le Chatelier's principle.

Removing N2

The removal of N2 drives the forward reaction and the equilibrium shifts towards the right yielding more N2 in accordance with Le Chateliers principle.

Add NH3

The addition of NH3 will shift the equilibrium position towards the left hand side according to Le Chateliers principle.

d) addition of argon has no effect on the equilibrium position.

e) increasing the temperature

Since the reaction is exothermic, increasing the temperature favours the reverse reaction and the equilibrium position his shifted towards the left hand side.

f) Decrease in volume;

Decreasing the volume favours the forward reaction hence the equilibrium position is shifted towards the right.

g) addition of a catalyst has no effect on the equilibrium position.

3 0
3 years ago
If 18.7 ml of 0.01500 Maqueous HCl is required to titrate 15.00 ml of an aqueous solution of NaOH to
ValentinkaMS [17]

Answer:

The molarity of  NaOH is 0.02 M.

Explanation:

Given data:

Volume of HCl = 18.7 mL

Molarity of HCl = 0.01500 M

Volume of NaOH = 15.00 mL

Molarity of NaOH = ?

Solution:

M₁V₁  = M₂V₂

0.01500 M × 18.7 mL  = M₂ ×  15.00 mL

M₂ = 0.3 M.mL /15.00 mL

M₂ = 0.02 M

The molarity of  NaOH is 0.02 M.

8 0
3 years ago
How many moles are in a 7.40-g sample of copper?
kolbaska11 [484]

Answer:

0.11645 moles

Explanation:

moles=n

M is molar mass of substance

m is in grams

n=m/M

So, 7.40/63.546 = 0.11645

0.116(rounded to sig figs)

3 0
3 years ago
Read 2 more answers
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