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Tasya [4]
3 years ago
7

You are a scientist working on increasing the efficiency of appliances to waste less

Chemistry
2 answers:
Neporo4naja [7]3 years ago
8 0

Answer: lightbulb 1: 200 joules in, 50 joules wasted, 150 joules out

Explanation:

Alex17521 [72]3 years ago
7 0

Lightbulb 1 has the lowest  percentage of energy lost as waste : 25%

<h3>Further explanation</h3>

Given

The input, output, and waste energy of Lightbulb

Required

The lowest  percentage of energy lost as waste.

Solution

Lightbulb 1 :

\tt \%energy~lost=\dfrac{50}{200}\times 100\%=25\%

Lightbulb 2 :

\tt \%energy~lost=\dfrac{30}{100}\times 100\%=30\%

Lightbulb 3:

\tt \%energy~lost=\dfrac{100}{150}\times 100\%=66.7\%

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The complete equation for this reaction is,

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Among the compounds present in the reaction, Barium Nitrate, Sodium Phosphate and Sodium Nitrate are soluble ionic compounds. Hence, they will completely ionize into ions. Only BaSO4 is insoluble which becomes the precipitate. Ionic equation is:

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