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2 years ago

PLS PLS HELP HELP ME ITS EASY ITS FREE PONTS LOL

Mathematics

2 answers:

vazorg [7]2 years ago

6 0

Answer:

58 degrees

Step-by-step explanation:

90-32

=58

~rere

s2008m [1.1K]2 years ago

4 0

Answer:

angle b measures 58°

Explanation:

As we know that, the sum of complementary angles is always equal to 90°.

Therefore,

angle a + angle b = 90°

32° + angle b = 90°

angle b = 90° - 32°

angle b = 58°

HOPE THIS HELPS AND HAVE A NICE DAY <3

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A rectangular flower garden in Samantha's backyard has 220 feet around its edge. The width of the garden is 50 feet. What is the

Ede4ka [16]

Answer: 60 ft

Step-by-step explanation:

Given

The perimeter of the garden is $220\ ft$

The width of the garden is $50\ ft$

Suppose the length of the garden is $x$

Perimeter is the sum of the lengths of the sides

$\Rightarrow 220=2(x+50)\\\Rightarrow 110=x+50\\\Rightarrow x=60\ ft$

So, the length of the garden is $60\ ft$

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3 years ago

Which point is 12 units less than point Q?

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Step-by-step explanation:

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3 years ago

What is the slope of this line? Answer: -1/5 1/5 5 -5

algol13

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3 years ago

How can find the estimate of the sum of the two fractions

vodka [1.7K]

Answer:

To make a high estimate for the sum of two fractions, find the commnon denominator and add them.

Step-by-step explanation:

To make a high estimate for the sum of two fractions in a word problem, rhe following steps are required.

Let the two fractions be represented as and

To perfrom the operation +

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6 0

3 years ago

Use the disk method or the shell method to find the volumes of the solids generated by revolving the region bounded by the graph

diamong [38]

Answer:

a) 8π

b) 8/3 π

c) 32/5 π

d) 176/15 π

Step-by-step explanation:

Given lines : y = √x, y = 2, x = 0.

a) The x-axis

using the shell method

y = √x = , x = y^2

h = y^2 , p = y

vol = ( 2π ) $\int\limits^2_0 {ph} \, dy$

= $( 2\pi ) \int\limits^2_0 {y.y^2} \, dy$

∴ Vol = 8π

b) The line y = 2 ( using the shell method )

p = 2 - y

h = y^2

vol = ( 2π ) $\int\limits^2_0 {ph} \, dy$

= $( 2\pi ) \int\limits^2_0 {(2-y).y^2} \, dy$

= ( 2π ) * [ 2/3 * y^3 - y^4 / 4 ] ²₀

∴ Vol = 8/3 π

c) The y-axis ( using shell method )

h = 2-y = h = 2 - √x

p = x

vol = $(2\pi ) \int\limits^4_0 {ph} \, dx$

= $(2\pi ) \int\limits^4_0 {x(2-\sqrt{x} ) } \, dx$

= ( 2π ) [x^2 - 2/5*x^5/2 ]⁴₀

vol = ( 2π ) ( 16/5 ) = 32/5 π

d) The line x = -1 (using shell method )

p = 1 + x

h = 2√x

vol = $(2\pi ) \int\limits^4_0 {ph} \, dx$

Hence vol = 176/15 π

attached below is the graphical representation of P and h

3 0

3 years ago