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2 years ago

Find the exact value of sec (–660)°

Mathematics

1 answer:

Nostrana [21]2 years ago

8 0

Add full rotations of 360° degree until the angle of between 0° and 360°.
Sec (60)
The exact value is sec (60) is 2

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Please help if know the answers

klio [65]

Answer:

2x-3

x =3 /2

and second one is -y+2

= -2/1

-2

6 0

2 years ago

Helppppppppppppppppppp helppppppppppppp

Annette [7]

HOPE ITS HELPFUL ^_^

<h2>•RHONA</h2>

3 0

2 years ago

How to answer this? TvT

ASHA 777 [7]

Since the midpoint lies on the axis, both ends are therefore equidistant from the axis and are mirrors of each other so..

Q = (4,9)

8 0

3 years ago

You have 88 grams of a radioactive kind of actinium. How much will be left after 44 years if its half-life is 22 years?

mash [69]

Answer:

22 grams

Step-by-step explanation:

loses 50% of it's mass per 22 years

so after 22 years the mass would be 44 grams

22 years later would leave 50% of 44 grams = 22 grams

3 0

2 years ago

The combined average weight of an okapi and a llama is 450450 kilograms. The average weight of 33 llamas is 190190 kilograms mor

Nataliya [291]

Answer:

Okapi 290 kg

Llama 160 kg

Step-by-step explanation:

Let weight of each llama be $l$

Let weight of each okapi be $o$

Given, combined weight of 1 okapi and 1 llama is 450, we can write:

$l+o=450$

Also, average weight of 3 llama is 190 more than the average weight of 1 okapi, thus we can write:

$3l-190=o$

Now, substituting 2nd equation into 1st equation, we can solve for weight of 1 llama:

$l+o=450\\l+(3l-190)=450\\l+3l-190=450\\4l=450+190\\4l=640\\l=\frac{640}{4}=160$

Each llama weights 160 kg, now using this and plugging into 2nd equation, we get weight of 1 okapi to be:

$o=3l-190\\o=3(160)-190\\o=290$

Each okapi weigh 290 kg

5 0

3 years ago