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gtnhenbr [62]
3 years ago
10

Find the exact value of sec (–660)°

Mathematics
1 answer:
Nostrana [21]3 years ago
8 0
Add full rotations of 360° degree until the angle of between 0° and 360°.
Sec (60)
The exact value is sec (60) is 2
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12x - 5 = 8x - x + 50<br> Help please show work and check the solution
Inga [223]

Answer:

x = 11

Step-by-step explanation:

12x - 5 = 8x - x + 50 \\ 12x - 5 = 7x + 50 \\ 12x - 5 - 7x = 7x + 50 - 7x \\ 12x - 7x - 5 = 50  \\ 5x - 5 = 50 \\ 5x - 5 + 5 = 50 + 5 \\ 5x = 55 \\ x = 11

and check:

12(11) - 5 = 8(11) - (11) + 50 \\ 132 - 5 = 77 + 50 \\ 127 = 127

3 0
3 years ago
Please respond quickly
storchak [24]
A should be the right answer. Hope this helped!
6 0
3 years ago
Read 2 more answers
A company manufactures two different sizes of boat lifts. The smaller lift requires 1 hour in the welding department and 2 hours
qaws [65]

Answer:

  • The solution that optimizes the profit is producing 0 small lifts and 50 large lifts.
  • Below are all the steps explained in detail.
  • The graph is attached.

Explanation:

<u />

<u>1. Name the variables:</u>

  • x: number of smaller lifts
  • y: number of larger lifts

<u></u>

<u>2.  Build a table to determine the number of hours each lift requires from each department:</u>

<u></u>

Number of hours

                                        small lift    large lift   total per department

Welding department            1x             3y                x + 3y

Packaging department        2x             1y                2x + y

<u></u>

<u>3. Constraints</u>

  • 150 hours available in welding:         x + 3y ≤ 150
  • 120 hours available in packaging:   2x + y ≤ 120
  • The variables cannot be negative:    x ≥ 0, and y ≥ 0

Then you must:

  • draw the lines and regions defined by each constraint
  • determine the region of solution that satisfies all the constraints
  • determine the vertices of the solution region
  • test the profit function for each of the vertices. The vertex that gives the greatest profit is the solution (the number of each tupe that should be produced to maximize profits)

<u></u>

<u>4. Graph</u>

See the graph attached.

Here is how you draw it.

  • x + 3y ≤ 150
  • draw the line x + 3y = 150 (a solid line because it is included in the solution set)
  • shade the region below and to the left of the line

  • 2x + y ≤ 120
  • draw the line 2x + y ≤ 120 (a solid line because it is included in the solution set)
  • shade the region below and to the left of the line

  • x ≥ 0 and y ≥ 0: means that only the first quadrant is considered

  • the solution region is the intersection of the regions described above.

  • take the points that are vertices inside the solutoin region.

<u>5. Test the profit function for each vertex</u>

The profit function is P(x,y) = 25x + 90y

The vertices shown in the graph are:

  • (0,0)
  • (0,50)
  • (42,36)
  • (60,0)

The profits with the vertices are:

  • P(0,0) = 0
  • P(0,50) = 25(0) + 90(50) = 4,500
  • P(42,36) = 25(42) + 90(36) = 4,290
  • P(60,0) = 25(60) + 90(0) = 1,500

Thus, the solution that optimizes the profit is producing 0 smaller lifts and 90 larger lifts.

3 0
3 years ago
Factoring polynomials HELP please step by step for extra points!
jok3333 [9.3K]
First you multiply the last term by the first term (3h+16h+15). Then find numbers that add to 16 and multiply to 15 then add or subtract it from (3h+15)(3h+1). Then factor if possible (h+5)(3h+1)
8 0
3 years ago
I need help please ASAP full points
kotegsom [21]

The best way to solve this problem is with a simple equation: part = percent (in decimal form) x whole

In this problem, we're trying to solve for the <em>whole </em>amount that the camera can hold, so we'll assign that the variable w.

We can use the information they gave us - 96 is the <em>part</em>, and 24% is the percent. We'll convert that to decimal form - 0.24

Then, we just plug these values back into the above equation:

96 = 0.24w

Divide both sides by 0.24 to get w on it's own, and you have your answer!

400 = w

Therefore, the memory card can hold up to 400 pictures.


Note: this equation is <em>super </em>helpful. It's good to have on hand for any problem involving percents, because you can solve for the part, percent, or whole depending on the problem.

4 0
3 years ago
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