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Luba_88 [7]
3 years ago
15

Find the product of (5.226)•(0.037)=

Mathematics
2 answers:
Alenkasestr [34]3 years ago
6 0

Answer:

ans is 0.193362................

nlexa [21]3 years ago
3 0

Answer: (5.226) x (0.037) = 0.193362

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Factor completely 3x3 − 6x2 − 24x. 3x(x − 4)(x + 2) 3x(x + 4)(x − 2) 3x(x − 3)(x − 2) 3x(x + 3)(x − 2)
inysia [295]

Answer:

3x(x - 4)(x + 2)

Step-by-step explanation:

Given

3x³ - 6x² - 24x ← factor out common factor of 3x from each term

= 3x(x² - 2x - 8) ← factor the quadratic

Consider the factors of the constant term (- 8) which sum to give the coefficient of the x- term.

The factors are - 4 and + 2, since

- 4 × 2 = - 8 and - 4 + 2 = - 2, thus

x² - 2x - 8 = (x - 4)(x + 2) and

3x³ - 6x² - 24x = 3x(x - 4)(x + 2)

7 0
3 years ago
What is (5,2) and (2,8) in slope intersect form?
yaroslaw [1]

Answer:

-3,6

Step-by-step explanation:

i think this is right

6 0
3 years ago
Can someone solve this?
Gemiola [76]

Answer:

B : 4x\sqrt{17}

Step-by-step explanation:

If you divide a rhombus using its diagonals, you get 4 right triangles, whose legs are both 1/2 the length of the diagonals.

This means that the legs of one of those 4 triangles have lengths of 2x/2, and 8x/2, so the legs of one of those triangles x and 4x. This makes the length of one side equal to \sqrt{x^{2} + (4x)^{2}} = \sqrt{17x^2} = x\sqrt{17}. Because all 4 sides are the same length, you multiply this value by 4, and get 4x\sqrt{17}, which is B.

4 0
3 years ago
In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b
madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding (ax+by)^7 using Binomial expansion, we have that:

(ax+by)^7 =

(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7

= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7

We have that the coefficients of the first two terms are 128 and -224.

For the first term:

=> a^7 = 128

=> a = \sqrt[7]{128}\\ \\\\a = 2

For the second term:

a^6b = -224

b = \frac{-224}{a^6}

b = \frac{-224}{2^6} \\\\\\b = \frac{-224}{64} \\\\\\b = 3.5

Therefore, a = 2, b = 3.5

5 0
3 years ago
One fourth of a number is 5. find the number​
Tems11 [23]

Hope this helps. Please mark brainliest

Answer: 20

let the number be x

1/4 x = 5

x=5*4

x=20

5 0
3 years ago
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