A store buys 13 sweaters for $52 and sells them for $377. How much profit does the store make per sweater?

Mathematics

2 answers:

Fed [463]2 years ago

8 0

$25 because 13 divided by 52 is $4 so $4 per sweater and $377 dived by 13 is $29 per sweater

elena-s [515]2 years ago

5 0

Answer:

Step-by-step explanation:

So, 13 sweaters cost $52, so 1 sweater costs $4. If he sells the 13 sweaters for $377, you will need to do 377 divided by 13, and that is 29. The last step you have to do is find the difference (subtraction) of 4 and 29. So, 29-4=25. Therefore, The profit the store made was $25 per sweater. Hoped that helped!!

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The table shows the height of water in a pool as it is being filled. A table showing Height of Water in a Pool with two columns

icang [17]

Answer:

The height of the water increases 2 inches per minute.

Step-by-step explanation:

the slope is always the ratio of

y coordinate change / x coordinate change

in our case, x is the time (minutes), and y is the water height (inches).

we see, the longer the pool get filled, the higher the water gets. logical, right ?

by checking the data points we see :

with every 2 minutes passing the water height increases by 4 inches.

so, the slope is +4/+2 = 2/1 = 2

and that ratio tells us now the increase of the water height with every fraction or multiple of the measured 2-minute interval.

every 2 minutes 4 inches more.

so, e.g. every 3×2 = 6 minutes we get 3×4 = 12 inches more.

and - every 1/2 × 2 = 1 minute more we get 1/2 × 4 = 2 inches more.

4 0

1 year ago

In a certain function, y varies directly with x. If y = 6 when x = 8, find x when y = 9.

Hatshy [7]

If y = 6 when x = 8, then value of "x" when y = 9 is equal to 12

<u>Solution:</u>

Given that , In a certain function, y varies directly with x

And x = 8 when y = 6,

We have to find what will be the value of x when y = 9

Now, from the given information,

$\begin{array}{l}{y \alpha x} \\\\ {y=c x \rightarrow(1)}\end{array}$

where c is the proportionality constant

$\begin{array}{l}{\text { Now, substitute } x=8 \text { and } y=6 \text { in }(1)} \\\\ {\rightarrow 8=c(6) \rightarrow c=\frac{8}{6}} \\\\ {\rightarrow c=\frac{4}{3}} \\\\ {\text { Then, }(1) \rightarrow x=\frac{4}{3} y} \\\\ {\text { So, when } y=9} \\\\ {\rightarrow x=\frac{4}{3}(9)} \\\\ {\rightarrow x=4 \times 3} \\\\ {\rightarrow x=12}\end{array}$