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spin [16.1K]
4 years ago
14

Which statements are true regarding the symmetry of the isosceles trapezoid? Check all that apply.

Mathematics
2 answers:
Ad libitum [116K]4 years ago
7 0

Answer:

1, 3, and 5

Step-by-step explanation:

Natali5045456 [20]4 years ago
6 0

Answer:

1 3 5

Step-by-step explanation:

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Which function has a vertex on the y-axis? f(x) = (x – 2)2 f(x) = x(x + 2) f(x) = (x – 2)(x + 2) f(x) = (x + 1)(x – 2)
strojnjashka [21]

we know that

If the vertex is on the y-axis, then the x-coordinate of the vertex is equal to zero

we are going to verify the vertex of each one of the functions to determine the solution

Remember that

The equation in vertex form of a vertical parabola is equal to

y=a(x-h)^{2} +k

where

(h,k) is the vertex

if a>0 -------> the parabola open upward (vertex is a minimum)

if a -------> the parabola open downward (vertex is a maximun)

<u>case A)</u> f(x)=(x-2)^{2}

This is a vertical parabola open upward

the vertex is the point (2,0)

therefore

The function f(x)=(x-2)^{2}  does not have a vertex on the y-axis

<u>case B)</u> f(x)=x(x+2)

f(x)=x(x+2)=x^{2}+2x

convert to vertex form

Complete the square. Remember to balance the equation by adding the same constants to each side.

f(x)+1=x^{2}+2x+1

Rewrite as perfect squares

f(x)+1=(x+1)^{2}

f(x)=(x+1)^{2}-1

the vertex is the point (-1,-1)

therefore

The function f(x)=x(x+2) does not have a vertex on the y-axis

<u>case C)</u> f(x)=(x-2)(x+2)

f(x)=(x-2)(x+2)=x^{2}-2^{2}

f(x)=x^{2}-4

the vertex is the point (0,-4)

The x-coordinate of the vertex is equal to zero

therefore

The function f(x)=(x-2)(x+2) has a vertex on the y-axis

<u>case D)</u> f(x)=(x+1)(x-2)

f(x)=(x+1)(x-2)\\ \\f(x)= x^{2}-2x+x-2 \\ \\f(x)= x^{2} -x-2

convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

f(x)+2= x^{2} -x

Complete the square. Remember to balance the equation by adding the same constants to each side.

f(x)+2+0.25= x^{2} -x+0.25

f(x)+2.25= x^{2} -x+0.25

Rewrite as perfect squares

f(x)+2.25= (x-0.50)^{2}

f(x)=(x-0.50)^{2}-2.25

the vertex is the point (0.5,-2.25)

therefore

The function f(x)=(x+1)(x-2) does not have a vertex on the y-axis

<u>the answer is</u>

f(x)=(x-2)(x+2)

6 0
3 years ago
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Given a rectangular prism with width and height = 4x and length = 10x-6. The expression for the surface area of the rectangular
777dan777 [17]

3

is the simplify expression

Step-by-step explanation:

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2 years ago
The amounts that two partners invested in a new business are given in the table above. If the partners share the profits in the
lora16 [44]
They cant it with the money
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Solve x/-4 &gt; 8<br><br> 1. x &gt; -2<br> 2. x &lt; -32<br> 3. x &lt; -2<br> 4. x &gt; -32
Gnom [1K]

Answer:

x<-32

Step-by-step explanation:

I hope this helped have a good night

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3 years ago
PLEASE ANSWER QUICKLY!! I NEED THIS ANSWER ASAP
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Answer:

you can use a website called wolfram alpha to help with any math equation

Step-by-step explanation:

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3 years ago
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