Answer:
option c is correct answer
Answer:
or ![Probability = 0.2](https://tex.z-dn.net/?f=Probability%20%3D%200.2)
Step-by-step explanation:
Given
![Black = 25](https://tex.z-dn.net/?f=Black%20%3D%2025)
![White = 35](https://tex.z-dn.net/?f=White%20%3D%2035)
![Red = 40](https://tex.z-dn.net/?f=Red%20%3D%2040)
Required
Determine the probability of selecting Black and Red
First, we need to calculate the number of red and black balls
The probability is calculated as thus:
![Probability = P(Black\ and \ Red) \ or\ P(Red\ and \ Black)](https://tex.z-dn.net/?f=Probability%20%3D%20P%28Black%5C%20and%20%5C%20Red%29%20%5C%20or%5C%20P%28Red%5C%20and%20%5C%20Black%29)
Convert to mathematical expressions
![Probability = [P(Black) *P(Red)] + [P(Red) *P(Black)]](https://tex.z-dn.net/?f=Probability%20%3D%20%5BP%28Black%29%20%2AP%28Red%29%5D%20%2B%20%5BP%28Red%29%20%2AP%28Black%29%5D)
Solve for each probaility;
![P(Black) = \frac{Black}{Total} = \frac{25}{100}](https://tex.z-dn.net/?f=P%28Black%29%20%3D%20%5Cfrac%7BBlack%7D%7BTotal%7D%20%3D%20%5Cfrac%7B25%7D%7B100%7D)
![P(Red) = \frac{Red}{Total} = \frac{40}{100}](https://tex.z-dn.net/?f=P%28Red%29%20%3D%20%5Cfrac%7BRed%7D%7BTotal%7D%20%3D%20%5Cfrac%7B40%7D%7B100%7D)
So, we have:
![Probability = [P(Black) *P(Red)] + [P(Red) *P(Black)]](https://tex.z-dn.net/?f=Probability%20%3D%20%5BP%28Black%29%20%2AP%28Red%29%5D%20%2B%20%5BP%28Red%29%20%2AP%28Black%29%5D)
![Probability = [\frac{25}{100} *\frac{40}{100}] + [\frac{40}{100} *\frac{25}{100}]](https://tex.z-dn.net/?f=Probability%20%3D%20%5B%5Cfrac%7B25%7D%7B100%7D%20%2A%5Cfrac%7B40%7D%7B100%7D%5D%20%2B%20%5B%5Cfrac%7B40%7D%7B100%7D%20%2A%5Cfrac%7B25%7D%7B100%7D%5D)
![Probability = [\frac{1000}{10000}] + [\frac{1000}{10000}]](https://tex.z-dn.net/?f=Probability%20%3D%20%5B%5Cfrac%7B1000%7D%7B10000%7D%5D%20%2B%20%5B%5Cfrac%7B1000%7D%7B10000%7D%5D)
![Probability = [\frac{1}{10}] + [\frac{1}{10}]](https://tex.z-dn.net/?f=Probability%20%3D%20%5B%5Cfrac%7B1%7D%7B10%7D%5D%20%2B%20%5B%5Cfrac%7B1%7D%7B10%7D%5D)
![Probability = \frac{1+1}{10}](https://tex.z-dn.net/?f=Probability%20%3D%20%5Cfrac%7B1%2B1%7D%7B10%7D)
![Probability = \frac{2}{10}](https://tex.z-dn.net/?f=Probability%20%3D%20%5Cfrac%7B2%7D%7B10%7D)
![Probability = \frac{1}{5}](https://tex.z-dn.net/?f=Probability%20%3D%20%5Cfrac%7B1%7D%7B5%7D)
or
![Probability = 0.2](https://tex.z-dn.net/?f=Probability%20%3D%200.2)
Answer:
b. Not binomial: there are more than two outcomes for each trial.
Step-by-step explanation:
Binomial probability distribution:
We need
Fixed number of trials.
Independent trials.
Each trial can be reduced to a yes/no proposition.
Rolling a single "loaded die 19 times, keeping track of the numbers that are rolled.
There are six possible outcomes(1,2,3,4,5,6), so cannot be reduced to a yes/no proposition, and the answer is given by option b.
Answer:
ok.
Step-by-step explanation:
Not a question.
Answer:
its 4
Step-by-step explanation:
cam got it wrong because cam should have used -2 as his division since the factor was x-3 to be specific in the fator x is a positive but the 2 is a negative but he put a positive 2