Answer:
Hope it may help u
Step-by-step explanation:
The sum of two numbers is 44 and their difference is 14. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.
The sum of x and y is 44. In other words, x plus y equals 44 and can be written as equation A:
x + y = 44
The difference between x and y is 14. In other words, x minus y equals 14 and can be written as equation B:
x - y = 14
Now solve equation B for x to get the revised equation B:
x - y = 14
x = 14 + y
Then substitute x in equation A from the revised equation B and then solve for y:
x + y = 44
14 + y + y = 44
14 + 2y = 44
2y = 30
y = 15
Now we know y is 15. Which means that we can substitute y for 15 in equation A and solve for x:
x + y = 44
x + 15 = 44
X = 29
Summary: The sum of two numbers is 44 and their difference is 14. What are the two numbers? Answer: 29 and 15 as proven here:
Sum: 29 + 15 = 44
Difference: 29 - 15 = 14
23 for 5=6
Step-by-step explanation:
The value of x, y and z from the system of equation are -1, -8 and 5 respectively.
Data;
- -2x + 6y + 3z = -31
- -3y + 7z = 59
- 2z = 10
<h3>System of Equation</h3>
To solve this problem, we have to solve the system of equation using substitution method.
From equation (iii)

let us substitute the value of z into equation (ii)

Let's substitute the value of x and y into equation (i)

From the calculation above, the value of x, y and z are -1, -8 and 5 respectively.
Learn more on system of equations here;
brainly.com/question/14323743
Answer:
a) Cancellations are independent and similar to arrivals.
b) 22.31% probability that no cancellations will occur on a particular Wednesday
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given time interval.
Mean rate of 1.5 per day on a typical Wednesday.
This means that 
(a) Justify the use of the Poisson model.
Each wednesday is independent of each other, and each wednesday has the same mean number of cancellations.
So the answer is:
Cancellations are independent and similar to arrivals.
(b) What is the probability that no cancellations will occur on a particular Wednesday
This is P(X = 0).


22.31% probability that no cancellations will occur on a particular Wednesday