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SashulF [63]
2 years ago
15

William decides to complete his reading homework for the past two days. The first day he was assigned to read 10 pages and the s

econd day he was assigned to read 15 pages. If William already read 13 pages, how many more pages does he need to read to complete his homework?
Mathematics
1 answer:
romanna [79]2 years ago
7 0
Too many
But maybe try Joe
Joe mama
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Why the systems must have the same solution?system(a)4x-5y=13.....3x+6y=11........system(b) 8x-10y=26.....x-11y=2.........AKA QU
Y_Kistochka [10]
When you add the equations in (a) you get 7x+y=24.

When you subtract the equations in (b) you also get 7x+y=24.

That means to solve both systems you can work with the same equation. However that is not enough. We must have two equivalent equations. We found only one.

Notice however that in the (b) we can take the first equation and divide every term by 2. When we do this we get 4x-5y=13. That’s the first equation in (a).

So both systems can be solved by working with the same two equations. These are 5x-5y=13 and 7x+y=24. And since we have two equations and two unknowns (the number of equations matches the number of variables) there is only one solution — one x and y that would make both systems true — solve both systems.

Basically we showed the systems are equivalent!
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A store charges a restocking fee for any returned item based upon the item price. An item priced at $200 has a fee of $12. An it
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Divide the restocking fee by the price of the item:


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Find the HCF of<br> x^4 y^2 and x^3 y^3
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Here's your answer down here↓:

Step-by-step explanation:

x^3 - y^3 = (x - y)(x^2 + xy + y^2)

(x^4 - y^4) = (x^2 - y^2)(x^2 + y^2) = (x - y)(x + y)(x^2 + y^2)

Ok. So the factor (x-y) appears once in the top line and once in the second line. So we are going to take it the least amount of times.

So, the factor (x + y) appears in the top line zero times and in the second line one time so we will take it where it appears the least which is zero times so we are still at (x - y)

And it Same goes for the factors of (x^2 + y^2) and (x^2 + xy + y^2)

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