Answer:
the correct answer is
Step-by-step explanation:
hope this helps u!!
To find the measure of angle a, subtract 151 from 180. (Reason: line w equals 180º, and the second angle is the same size as the 151º angle.)
180 - 151 = 29
<h2>Answer:</h2>
<u>Angle a = </u><u>29º</u>
Here is your answer. Good luck!
Answer:
All possible are:
(G,L,S)
(G,L,R)
(G,L,P)
(G,S,R)
(G,S,P)
(G,R,P)
(L,S,R)
(L,S,P)
(S,R,P)
{L,R,P)
Probability of 1st/2nd/10th sample = 1/10
Step-by-step explanation:
All the possible combinations of the 3 size samples from a 5 size population have been listed without repetition.
Total Numbers of Samples = 10
To find the probability of finding the first sample from random sampling procedure,
Probability = Number of desired outcomes/ Total number of outcomes
Where Number of desired outcome is 1 and total number of outcomes is 10.
Probability = 1/10
Similarly, to find 2nd sample or 10th sample, the number of desired outcomes is same i.e 1, hecne the probability remains the same i.e 1/10
Answer:
Make an eqaution from here.
Let’s make evening 2 “x”
So the first evening has 9 less then the secon evening so…
x-9
Of course theres the second evening (x).
X-9+x
Then the third evening has 4 times as much as the second meeting so…
x-9+x+4x
And when solved, it has to equal 105.
So solve from here.
Combine like terms.
6x-9=105
Isolate
6x=114
x= 19
First evening is 9 less then 19, so 10.
The second evening was 19 calls.
The third evening was 4 times the second evening so, 19*4= 76
1st night = 10
2nd night= 19 calls
Thrid night= 76 calls