7and 2 3rds divided by 5 and 3 8ths is more then one
What
ask the question I will answer it
go ahead ask
Answer:
first one : (7+12+3+4+4+8)*2=76
Answer:
there is no figure
Step-by-step explanation:
attach a photo first
S = ut + (1/2)a(t²) Subtract ut from both sides
(1/2)a(t²) = S - ut Multiply both sides by 2
a(t²) = 2s - 2ut Divide both sides by t²
a= 2s/t² - 2u/t
a= (2S - 2ut)/t²
Answer is C) but there should be parentheses around the term (2S-2ut)