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GrogVix [38]
2 years ago
13

Answer number 3 and 4 please. Thank you.

Mathematics
1 answer:
notka56 [123]2 years ago
5 0
3:80
4:20 those are the answers
You might be interested in
What is the value of 3-6(z-2) if z=-2
krek1111 [17]

Answer:

27

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

3 - 6(z - 2)

z = -2

<u>Step 2: Evaluate</u>

  1. Substitute in <em>z</em>:                   3 - 6(-2 - 2)
  2. (Parenthesis) Subtract:      3 - 6(-4)
  3. Multiply:                              3 + 24
  4. Add:                                    27
6 0
3 years ago
Read 2 more answers
HURRY Which is an equation in point-slope form for the line that passes through the points (−1,4) and (3,−4) ?
mash [69]

Answer:

y-4=-2(x+1)

Step-by-step explanation:

y-y1=m(x-x1)

m=(y2-y1)/(x2-x1)

m=(-4-4)/(3-(-1))

m=-8/(3+1)

m=-8/4

m=-2

y-4=-2(x-(-1))

y-4=-2(x+1)

7 0
4 years ago
What is the area of an equilateral triangle with perimeter 24 inches?
Anna11 [10]
Divide the perimeter by 3 to get 8 then use the equation for the area of a triangle (a= BH1/2) and your answer is 32
8 0
3 years ago
Can someone explain how to factor a number like in the picture I attached? Thank you!
xenn [34]

hey man im sorry i just need points because im strugling

Step-by-step explanation:

5 0
3 years ago
Find the difference between points M(6,16) and Z(-1,14) to the nearest tenth.
svlad2 [7]

I'm not sure what you mean by difference, so I am guessing you meant to write "distance". If this is not the case, then feel free to report me. Anyway, to find the distance between two points you would use the distance formula.

Distance Formula: d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.

Let's substitute our point coordinates into the formula. We'll substitute -1 and 6 for x_2 and x_1, and 14 and 16 for y_2 and y_1. After substituting, your formula will now look like: d=\sqrt{(-1-6)^2+(14-16)^2}.

d=\sqrt{(-1-6)^2+(14-16)^2}

Subtract the coordinates.

d=\sqrt{(-7)^2+(-2)^2}

Square the subtracted coordinates.

d=\sqrt{49+4}

Add 49 and 4.

d=\sqrt{53}

Square root 53 and round the answer to the nearest tenth.

7.28 becomes 7.3.

7.3 units is the distance between points M and Z.

5 0
4 years ago
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