Answer:
The ratio of the difference of the two means to Sidney's mean absolute deviation = 
= 1.2195
Step-by-step explanation:
P.S - The exact question is -
Given - The means and mean absolute deviations of Sidney’s and Phil’s grades are shown in the table below.
Sidney’s Grades Phil’s Grades
Mean 82 78
Mean Absolute Deviation 3.28 3.96
To find - Which expression represents the ratio of the difference of the two means to Sidney’s mean absolute deviation?
Proof -
Given that Mean of Sidney Grades = 82
Mean of Phil's Grades = 78
So,
The difference of two means = 82 - 78 = 4
Also,
Given, Mean Absolute Deviation of Sydney = 3.28
Now,
The ratio of the difference of the two means to Sidney's mean absolute deviation = = 1.2195
Answer:
Step-by-step explanation:
The vertex would be the highest/lowest point so lets factor this first
when we factor we get
2(x^2+6x+8)
2(x+4) (x+2)
Using zero product property we find the 2 x values and x intercepts are
-4 and -2
the middle point of these points is -3
Substitute -3 for x and solve
2(-3+4) (-3+2)
2 * 1 * -1
2*-1
-2
(-3,-2) is the vertex
<span>I note that this problem starts out with "Which is a factor of ... " This implies that you were given several answer choices. If that's the case, it's unfortunate that you haven't shared them.
I thought I'd try finding roots of this function using synthetic division. See below:
f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35
Please use " ^ " to denote exponentiation. Thanks.
Possible zeros of this poly are factors of 35: plus or minus 1, plus or minus 5, plus or minus 7. Use synthetic division; determine whether or not there is a non-zero remainder in each case. If none of these work, form rational divisors from 35 and 6 and try them: 5/6, 7/6, 1/6, etc.
Provided that you have copied down the function
</span>f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35 properly, this approach will eventually turn up 1 or 2 zeros of this poly. Obviously it'd be much easier if you'd check out the possible answers given you with this problem.
By graphing this function, I found that the graph crosses the x-axis at 7/2. There is another root.
Using synth. div. to check whether or not 7/2 is a root:
___________________________
7/2 / 6 -21 -4 24 -35
21 0 -14 35
----------- ------------------------------
6 0 -4 10 0
Because the remainder is zero, 7/2 (or 3.5) is a root of the polynomial. Thus, (x-3.5), or (x-7/2), is a factor.
Integers are positive and negative whole numbers no fractions or decimals.
Real numbers do have fractions and decimals that integers do not.
Answer:
3×5×53
Step-by-step explanation:
You can use divisibility rules to find the small prime factors.
The number ends in 5, so is divisible by 5.
795/5 = 159
The sum of digits is 1+5+9 = 15; 1+5 = 6, a number divisible by 3, so 3 is a factor.
159/3 = 53 . . . . . a prime number,* so we're done.
795 = 3×5×53
_____
* If this were not prime, it would be divisible by a prime less than its square root. √53 ≈ 7.3. We know it is not divisible by 2, 3, or 5. We also know the closest multiples of 7 are 49 and 56, so it is not divisible by 7. Hence 53 is prime.
