<h3>
Answer:</h3>
Factor 6 from the first two terms.
<h3>
Step-by-step explanation:</h3>
By factoring out "a", you can better see what "h" needs to be.
- y = 6(x^2 +3x) +14 . . . . 6 factored from first 2 terms
- add the square of half the x-coefficient inside parentheses; add the opposite outside: y = 6(x^2 +3x +2.25) +14 -6(2.25)
- rewrite as a square; combine the constants: y = 6(x+1.5)^2 +0.5
So for the first one it is (x-3)(x+3) this is because it is a difference of squares so you square root the 9 and the minus you do both +and - in order to keep up the -9
The zeros are:x=3 and x=-3 ( this is because you change the sign in the bracket
the others should be pretty simple to do for number 2 its a complex
the third is a simple trinomial
and fourth is simple trinomial as well
Answer:
246.76$
Step-by-step explanation:
199 x .24 =
47.76
199 + 47.76 =
246.76
Answer:
43
Step-by-step explanation:
Let
The unit digit = x
The tens digit = y
The number = 10x + y
The tens digit of a two-digit number is five more than the units digit.
y = x + 5
Seven times the sum of the digits of this number is 3 less than the number itself.
7(x + y) = 10x + y - 3
7x + 7y = 10x + y - 3
Find the number.
We substitute x + 5 for y
7x + 7(x + 5) = 10x + (x + 5) - 3
7x + 7x + 35 = 10x + x + 5x - 3
14x + 35 = 11x + 5x - 3
Collect like terms
35 + 3 = 11x + 5x -14x
38 = 16x - 14x
38 = 2x
x = 38/2
x = 19
Solving for y
y = x + 5
y = 19 + 5
y = 24
The number = 19 + 24
= 43
X = 4 , y = -1
Explanation:
solve by elimination ie eliminate x or y from the equations by performing operations on them.
first label the equations , to follow the process.
x - y = 5 ----------------(1)
x+ y = 3 ----------------(2)
If (1) and (2) are added then y will be eliminated.
(1) + (2) gives : 2x = 8 → x = 4
now substitute this value of x into either of the 2 equations and solve for y.
let x = 4 in (1) : 4 - y = 5 → -y = 1 → y = -1
check in (1) : 4-(-1) = 4+1 = 5
check in(2) : 4 - 1 = 3
