Ask question

Ask question

All categories

gizmo_the_mogwai [7]

2 years ago

5

Prove that ABCD is not a parallelogram.

1 answer:

spayn [35]2 years ago

8 0

Answer:

Segment AD is 4 units long, while segment BC is 5 units long. If this figure was a parallelogram, these two segments would be equal to each other.

Step-by-step explanation:

You might be interested in

Find the quotient 7.980 divided by 0.19

Advocard [28]

The answer 7980 divided by .19 =/is 42.

5 0

3 years ago

In the xy-plane, the point (4,4) lies on the graph of the function f(x)-2x2-bx + 12. What is the value of b?

nikdorinn [45]

Simply substitute the point into the given equation; as there is one variable, you only need one point and so one is given. When done so, you shall get b=4

5 0

3 years ago

Tom made 5,000 mL of soup. He packed 2.5 liters of the soup in his kids' lunches. He froze the rest of the soup. How many millil

MakcuM [25]

Answer:

Amount of frozen soup = 2500 mL

Step-by-step explanation:

We are told that tom made 5,000 mL of soup.

We are also told he packed 2.5 Litres into his kids' lunches.

Now, from conversions,

1 liter = 1000 mL

Thus,

2.5 litres = 2.5 × 1000 = 2500 mL

Now, we are told he froze the rest of the soup.

Thus;

Amount of frozen soup = total amount of soup made - amount given to kids' lunch pack.

Amount of frozen soup =

5000 - 2500 = 2500 ml

7 0

3 years ago

Which area model can u use to fine * find 39 x73

sweet [91]

The area model you can use is D , cs 70 +3 & 30+9

3 0

3 years ago

The general form of an parabola is 2x2−12x−3y+12=0 .

Murljashka [212]

Answer:

The standard form of the parabola is $(x-3)^2=4*\frac{3}{8}(y+2)$

Step-by-step explanation:

The standard form of a parabola is

$(x-h)^2=4p(y-k)$ .

In order to convert $2x^2-12x-3y+12=0$ into the standard form, we first separate the variables:

$2x^2-12x+3y+12=0\\\\2x^2-12x+12=3y$

we now divided both sides by 2 to remove the coefficient from $2x^2$ and get:

$x^2-6x+6=\frac{3}{2}y$ .

We complete the square on the left side by adding 3 to both sides:

$x^2-6x+6+3=\frac{3}{2}y+3$

$x^2-6x+9=\frac{3}{2}y+3$

$(x-3)^2=\frac{3}{2}y+3$

now we bring the right side into the form $4p(y-k)$ by first multiplying the equation by $\frac{2}{3}$ :

$\frac{2}{3} *(x-3)^2=\frac{2}{3} *(\frac{3}{2}y+3)\\\\\frac{2}{3} *(x-3)^2=y+2$

and then we multiplying both sides by $\frac{3}{2}$ to get

$(x-3)^2=\frac{3}{2} (y+2)$ .

Here we see that

$4p=\frac{3}{2}$

$\therefore p=\frac{3}{8}$

Thus, finally we have the equation of the parabola in the standard form:

$\boxed{(x-3)^2=4*\frac{3}{8}(y+2)}$

5 0

3 years ago