The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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Answer:
D
Step-by-step explanation:
We want to find the distance between (-6, 4) and (-8, 6).
We can use the distance formula given by:

Let (-6, 4) be (x₁, y₁) and let (-8, 6) be (x₂, y₂).
Substitute:

Evaluate:

Evaluate:

Hence, our answer is D.