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2 years ago

Consider the ratio table.

Mathematics

2 answers:

ziro4ka [17]2 years ago

7 0

Answer:

y = 8 and x=9

Step-by-step explanation:

2x4=8

9x4=36

Vinvika [58]2 years ago

3 0

Answer:

a) 8

b) 9

Step-by-step explanation:

4x= y or x : 1/4y

So when x=2, y=8 and when y=36, x=9

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Giving brainiest

mestny [16]

Answer:

7x2 is 14

I will adopt you

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Please help I have no clue how to do this

Alinara [238K]

Step-by-step explanation:

It's a question of trigonometry.

You need to remember that tangent (tan) stands for Perpendicular / Base.

So, tan P = QR / PR

By Pythagoras Theorem,

34² = 30² + x²

x² = 34² - 30²

x² = 1156 - 900

x² = 256

x = 16

Now, placing the values,

tan P = 30 / 16

tan P = 1.875

HOPE IT HELPS ^_^

5 0

3 years ago

Which group of numbers are all prime?

Nana76 [90]

C

This is because none of the numbers can be divided by any number other than themselves or 1.

5 0

3 years ago

Problem 10: A tank initially contains a solution of 10 pounds of salt in 60 gallons of water. Water with 1/2 pound of salt per g

AysviL [449]

Answer:

The quantity of salt at time t is $m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })$ , where t is measured in minutes.

Step-by-step explanation:

The law of mass conservation for control volume indicates that:

$\dot m_{in} - \dot m_{out} = \left(\frac{dm}{dt} \right)_{CV}$

Where mass flow is the product of salt concentration and water volume flow.

The model of the tank according to the statement is:

$(0.5\,\frac{pd}{gal} )\cdot \left(6\,\frac{gal}{min} \right) - c\cdot \left(6\,\frac{gal}{min} \right) = V\cdot \frac{dc}{dt}$

Where:

$c$ - The salt concentration in the tank, as well at the exit of the tank, measured in $\frac{pd}{gal}$ .

$\frac{dc}{dt}$ - Concentration rate of change in the tank, measured in $\frac{pd}{min}$ .

$V$ - Volume of the tank, measured in gallons.

The following first-order linear non-homogeneous differential equation is found:

$V \cdot \frac{dc}{dt} + 6\cdot c = 3$

$60\cdot \frac{dc}{dt} + 6\cdot c = 3$

$\frac{dc}{dt} + \frac{1}{10}\cdot c = 3$

This equation is solved as follows:

$e^{\frac{t}{10} }\cdot \left(\frac{dc}{dt} +\frac{1}{10} \cdot c \right) = 3 \cdot e^{\frac{t}{10} }$

$\frac{d}{dt}\left(e^{\frac{t}{10}}\cdot c\right) = 3\cdot e^{\frac{t}{10} }$

$e^{\frac{t}{10} }\cdot c = 3 \cdot \int {e^{\frac{t}{10} }} \, dt$

$e^{\frac{t}{10} }\cdot c = 30\cdot e^{\frac{t}{10} } + C$

$c = 30 + C\cdot e^{-\frac{t}{10} }$

The initial concentration in the tank is:

$c_{o} = \frac{10\,pd}{60\,gal}$

$c_{o} = 0.167\,\frac{pd}{gal}$

Now, the integration constant is:

$0.167 = 30 + C$

$C = -29.833$

The solution of the differential equation is:

$c(t) = 30 - 29.833\cdot e^{-\frac{t}{10} }$

Now, the quantity of salt at time t is:

$m_{salt} = V_{tank}\cdot c(t)$

$m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })$

Where t is measured in minutes.

7 0

3 years ago

In a game, if you roll a 6 on a 6-sided number cube, you lose a turn.

Julli [10]

A) the probability is 1 in 6 (1/6); there are six numbers and only one is 6, therefore 1 in 6
B) the probability is 5 in 6 (5/6); there are 6 numbers and only one is not 6, therefore 5 in 6
C) the probability of rolling a 6 is 1 in 6 and the probability of not rolling a 6 is 5 in 6
D) the probability is again 1 in 6 (1/6); 120 divided by 6 is 20, and 20/120 simplifies to 1/6
thats the best i can do to explain

4 0

3 years ago