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3 years ago

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Which of the following did Columbus NOT bring back with him from his voyages to the "New World"?

1 answer:

Andre45 [30]3 years ago

6 0

A, Native People

Hope this helps ;)

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Write a numerical expression that represents the quotient of 85 minus 7 and 19

disa [49]

Answer:

85-7-19 or 85-26

Step-by-step explanation:

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3 years ago

Patty bought cupcakes for her sister's birthday party. 15 out of the 25 cupcakes had sprinkles on top. What percentage of the cu

Dafna11 [192]

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60%

Step-by-step explanation:

15/25=.6

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2 years ago

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What is the mean, median, and mode of 6,2,3,4,4,2,8,5,2

bearhunter [10]

Answer:

Mode=2

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Step-by-step explanation:

Mode you add all the numbers and divide by the actual number of the numbers given.

Median you cancel the numbers from first to last until you reach the one in the middle that's going to be the median.

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3 years ago

What is the slope of the line?

WINSTONCH [101]

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4/5 or in decimal form .8

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2 years ago

The gate of a stadium ha two pillars each of height 10ft.with four visible lateral faces and 3ft*3ft bases .the top of eaxh pill

lbvjy [14]

The pillars and the pyramids in the stadium gate means that we have to calculate the area of the items that make up the gate one after the other. At the end of the calculation, the calculated areas are then added up.

The total cost of painting is Rs.21344

First, we calculate the area of 1 side of 1 pillar using:

$A = Height * Base$

Where

$Height = 10ft$ --- Height of the pillar

$Base = 3ft$ --- Base of the pillar

So:

$A = 10ft * 3ft$

$A = 30ft^2$

The area of the 4 sides of the pillar is:

$A_2 = 4 * A$ --- i.e. 4 multiplied by the area of 1 side

$A_2 = 4 * 30ft^2$

$A_2 = 120ft^2$

The area of the 2 pillars is:

$Area_1 = 2 * A_2$ --- i.e. 2 multiplied by the area if 1

$Area_1 = 2 * 120ft^2$

$Area_1 = 240ft^2$

Because one part of the pyramid won't be visible, we calculate the area of the pyramid using:

$Area = lw + l\sqrt{(w/2)^2 + h^2} + w\sqrt{(l/2)^2 + h^2}$

Where:

$h = 2$ -- the height

$l = w = 3$ --- the base of the pillar is the length and width of the pyramid.

So, we have:

$Area = 3\sqrt{(2/2)^2 + 2^2} + 3\sqrt{(2/2)^2 + 2^2}$

$Area = 3\sqrt{1 + 4} + 3\sqrt{1 + 4}$

$Area = 3\sqrt{5} + 3\sqrt{5}$

$Area = 6\sqrt{5}$

For the two pyramids, the area is:

$Area_2 = 2 * 6\sqrt 5$ -- 2 multiplied by area of 1

$Area_2 = 12\sqrt 5$

$Area_2 = 26.8$

So, the total area to be painted is:

$Total = Area_1 + Area_2$ --- the sum of the area of the pillars and the pyramids

$Total = 240+26.8$

$Total = 266.8ft^2$

The unit cost of paint is:

Rate = Rs80 per sq.ft

The total cost of painting is:

$Cost = 80 * 266.8$

$Cost = Rs.21344$

Read more at:

brainly.com/question/14320476

7 0

3 years ago