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Allisa [31]
2 years ago
9

Given n = (1,2) and m = (6,12), find the magnitude of 1/2m-2n

Mathematics
1 answer:
ser-zykov [4K]2 years ago
7 0

Step-by-step explanation:

\frac{1}{2} m - 2n

\frac{1}{2}  \binom{6}{12}  - 2 \binom{1}{2}

\binom{3}{6}  -  \binom{2}{ 4}

\binom{1}{2}

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If machanical advantage of simple machine is 4, what dose it indicates?​
Savatey [412]

Answer:

Velocity ratio of simple machine is the ratio of distance travelled by effort to the distance travelled by load in the machine.Mechanical advantage MA is the ratio of output (generated by the machine) force to input (applied to the machine) force. So MA = 4 means that for example if you apply 100 N then your machine will multiply that force and generate 400 N.

6 0
2 years ago
What are the best approximations of the solutions to this system?
Scilla [17]

(-1.2,-2.0) and (1.9,2.2) are the best approximations of the solutions to this system.

Option B

<u>Step-by-step explanation:</u>

Here, we have a graph of two functions from which we need to find the approximate value of common solutions. Let's find this:

First look at where we have intersection points, In first quadrant & in third quadrant.

<u>At first quadrant:</u>

Draw perpendicular lines from x-axis & y-axis from this point . After doing this we can clearly see that the perpendicular lines cut x-axis at x=1.9 and y-axis at y=2.2. So, one point is (1.9,2.2)

<u>At Third quadrant:</u>

Draw perpendicular lines from x-axis & y-axis from this point. After doing this we can clearly see that the perpendicular lines cut x-axis at x=-1.2 and y-axis at y=  -2.0. So, other point is (-1.2,-2.0).

5 0
3 years ago
What are the roots of this equation? x2-4x+9=0
zysi [14]

Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

In a quadratic function that has the form:

f(x)= ax² + bx + c

the zeros or roots are calculated by:

x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

<h3>This case</h3>

The quadratic function is f(x) = x² + 4x +9

Being:

  • a= 1
  • b= 4
  • c= 9

the zeros or roots are calculated as:

x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}

x1=\frac{-4+\sqrt{16-36 } }{2x1}

x1=\frac{-4+\sqrt{-20 } }{2x1}

and

x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}

x2=\frac{-4-\sqrt{16-36 } }{2x1}

x2=\frac{-4-\sqrt{-20} }{2x1}

If the content of the root is negative, the root will have no solution within the set of real numbers. Then \sqrt{-20} has no solution.

Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

Learn more about the zeros of a quadratic function:

brainly.com/question/842305

brainly.com/question/14477557

#SPJ1

6 0
1 year ago
Help please I need help fr fr
Digiron [165]

Answer:

See explanation!

Step-by-step explanation:

A = Reflection

B= Rotation

C= Translation

D= Dilation

8 0
2 years ago
Compare. Use &gt;, &lt;, or = to complete the statement. | –10 | | 11 | A. &gt; B. = C. &lt;
mash [69]
Answer: |-10| < |11|

So choice C. is right.

hope this helps!
6 0
3 years ago
Read 2 more answers
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