All categories

2 years ago

Given n = (1,2) and m = (6,12), find the magnitude of 1/2m-2n

Mathematics

1 answer:

ser-zykov [4K]2 years ago

7 0

Step-by-step explanation:

$\frac{1}{2} m - 2n$

$\frac{1}{2} \binom{6}{12} - 2 \binom{1}{2}$

$\binom{3}{6} - \binom{2}{ 4}$

$\binom{1}{2}$

You might be interested in

A basket ball team played six games. In those games, the team won by 8 points, lost by 10, won by 7, won by 10, lost by 3, and w

sergiy2304 [10]

Answer: 3

Step-by-step explanation:

Mean simply means average. To calculate mean,we add together all the numbers given and divide them by the amount of numbers.

The Mean here will be:

= [8 +(-10) + 7 + 10 + (-3) + 6]/6

=18/6

= 3

The mean is 3

6 0

3 years ago

Diana is painting statues. She has 7/8 fraction of a gallon of paint remaining. Each statue requires 1/6 of a gallon of paint. h

fomenos

She can paint almost 7 statues - 6.86 statues.

7/8 ÷ 1/6

21/24 ÷ 4/24

21/24 * 24/4 = 576/84

576 / 84 is approximately 6.86.

4 0

3 years ago

The ratio of a quarterback’s completed passes to attempted passes in 2:5. If he attempted 20 passes he completed. Round to the n

puteri [66]

If he attempted 45 passes, find how many passes he completed. Round to the nearest whole number of necessary.

8 0

3 years ago

Hannah has information about an object in circular orbit around Earth. MEarth = 6. 0 × 1024 kg G = 6. 67 × 10–11 StartFraction m

castortr0y [4]

In order to calculate the tangential speed of the orbiting object Hannah need the distance of the orbiting object to Earth.

<h3>What is the tangential speed of the object?</h3>

The tangential speed of an object is the linear component of the speed, which is moving in a circular path.

In terms of the gravitation constant, the tangential speed can be given as,

$v=\sqrt{\dfrac{Gm}{r}}$

Here, {<em>G</em>} is the gravitation constant, (<em>m</em>) is the mass and (<em>r</em>) is the radius.

Hannah has information about an object in circular orbit around Earth.

The mass of the earth is.

$m_E=6. 0 \times10^{24} kg$

The value of gravitational constant is,

$G=6. 67\times 10{-11}\rm Nm^2/kg^2$

The radius of the earth is,

$r_E=6. 0 \times 10^6 \rm m$

Here, only the distance of the orbiting object to Earth is need to find the tangential speed of the object.

Hence, in order to calculate the tangential speed of the orbiting object Hannah need the distance of the orbiting object to Earth.

Learn more about the tangential speed here;

brainly.com/question/4933588

7 0

2 years ago

What’s the measure ?

Ganezh [65]

Cvm jsjsjsjjshs shhshspp

7 0

3 years ago