An example of a direct variation scenario is the increase in the income of a start-up bakeshop when the number of cakes sold increase. Example data are (4, $ 100), (5, $ 125), (6, $ 150), and (7, $ 175).
The example of indirect variation scenario is the decrease in time it takes to reach a destination when the speed of the mobile increases. This is shown in the data points: (10 kph, 10 mins), (12 kph, 8 mins), (14 kph, 6 mins), and (16 kph, 4 mins).
Answer:
285.5
Step-by-step explanation:
Answer:
11.1 units
Step-by-step explanation:
We solve for this using the formula when using coordinates (x1 , y1) and (x2, y2)
= √(x2 - x1)² + (y2 - y1)²
A(5,2), B(5,4), and C(1,1).
For AB = √(x2 - x1)² + (y2 - y1)²
= A(5,2), B(5,4)
= √(5 - 5)² +(4 - 2)²
= √ 0² + 2²
= √4
= 2 units
For BC = √(x2 - x1)² + (y2 - y1)²
= B(5,4), C(1,1)
= √(1 - 5)² +(1 - 4)²
= √ -4² + -3²
= √16 + 9
= √25
= 5 units
For AC = √(x2 - x1)² + (y2 - y1)²
A(5,2), C(1,1)
= √(1 - 5)² + (1 - 2)²
= √-4² + -1²
= √16 + 1
= √17
= 4.1231056256 units
The Formula for the Perimeter of Triangle = Side AB + Side BC + Side AC
= 2 units + 5 units + 4.1231056256 units
= 11.1231056256 units.
Approximately the Perimeter of a Triangle to the nearest tenth = 11.1units
Im guessing either 2/3*570 or 1/3*5700
A) cos a = (√22)/5; tan a = (√66)/22
B) sin a = (2√2)/3; tan a = 2√2
C) sin a = (√30)/6; cos a = (√6)/6
D) sin a = 3/5; tan a = 3/4
E) sin a = (5√26)/26; cos a = (√26)/26
F) sin a = 3/5; tan a = 3/4
Explanation
The ratio for sine is opposite/hypotenuse. This means the side opposite the angle is √3 and the hypotenuse is 5. Using the Pythagorean theorem to find the adjacent side,
(√3)² + A² = 5²
3+A² = 25
A² = 22
A=√22
This means that cos a = adjacent/hypotenuse = (√22)/5 and tan a = opposite/adjacent = (√3)/(√22) = (√66)/22.
B) The ratio for cosine is adjacent/hypotenuse; this means the side adjacent to the angle is 1 and the hypotenuse is 3. Using the Pythagorean theorem to find the side opposite the angle (p),
1² + p² = 3²
1+p² = 9
p² = 8
p=√8 = 2√2
This means that sin a = opposite/hypotenuse = (2√2)/3 and tan a = opposite/adjacent = (2√2)/1 = 2√2.
C) The ratio for tangent is opposite/adjacent; this means that the side opposite the angle is √5 and the side adjacent the angle is 1. Using the Pythagorean theorem to find the hypotenuse,
(√5)²+1² = H²
5+1=H²
6=H²
√6 = H
This means that sin a = opposite/hypotenuse = (√5)/(√6) = (√30)/6 and cos a = adjacent/hypotenuse = 1/(√6) = (√6)/6.
D) The ratio for cosine is adjacent/hypotenuse; this means that the side adjacent the angle is 4 and the hypotenuse is 5. Using the Pythagorean theorem to find the side opposite the angle, p:
4²+p²=5²
16+p²=25
p²=9
p=3
This means that sin a = opposite/hypotenuse = 3/5 and tan a = opposite/adjacent = 3/4.
E) The ratio for tangent is opposite/adjacent;; this means that the side opposite the angle is 5 and the side adjacent the angle is 1. Using the Pythagorean theorem to find the hypotenuse,
5²+1²=H²
25+1=H²
26=H²
√26 = H
This means that sin a = opposite/hypotenuse = 5/(√26) = (5√26)/26 and cos a = adjacent/hypotenuse = 1/(√26) = √26/26.
F) 0.8 = 8/10; The ratio for cosine is adjacent/hypotenuse. This means that the side adjacent the angle is 8 and the hypotenuse is 10. Using the Pythagorean theorem to find the side opposite the angle, p:
8²+p² = 10²
64+p² = 100
p² = 36
p=6
This means that sin a = opposite/hypotenuse = 6/10 = 3/5 and tan a = opposite/adjacent = 6/8 = 3/4.
