- See charge on ion is -1 .
Hence it has taken 1 electron
Now first look at EC of Fluorine(F)
- Now one electron added .hence no of electrons is 10now
Look at the EC
Or
Option C is correct.
Look at the following balanced equation. How many atoms of oxygen (O) are present on the reactant side of the equation?
1 answer:
You might be interested in
The correct answer is .
Organometallic chemistry is the study of organometallic compounds, which are substances that contain at least one chemical bond between a carbon atom from an organic molecule and a metal. These substances include alkali, alkaline earth, and transition metals, as well as metalloids like boron, silicon, and selenium. In addition to links to organyl fragments or molecules, bonds to 'inorganic' carbon, such as those to carbon monoxide (metal carbonyls), cyanide, or carbide, are also typically regarded as organometallic. Although they are not strictly speaking organometallic compounds, some similar compounds, such as transition metal hydrides and metal phosphine complexes, are frequently included in discussions of such substances. The phrase "metalorganic compound," which is comparable but different, describes molecules that contain metals but do not have direct metal-carbon bonds but do have organic ligands.
Learn more about organometallic reagent here:
#SPJ4
Answer: 4.15234 m
512 g H2O * = 0.512 kg H2O
Nitric Acid: HNO3 = 1.008 + 14.007 + 3(15.999) = 63.012 g/mol
H = 1.008 g/mol
N = 14.007 g/mol
O3 = 3*15.999
134 g HNO₃ * = 2.126 mol
m = = 4.15234 m
Answer:
the concentration of the solution is 0.00906 M
Explanation:
Given the data in the question;
we know that from Nernst Equation;
E = E⁰ - ((0.0592/n) logQ)
now, E₀ for concentration cell is 0
n for this redox is 2
concentration of the unknown solution is x
so we substitute
0.045 = 0 - ( 0.0592 / 2)log( x/0.300 ))
0.045 = -0.0296log( x/0.300 )
divide both side by 0.0296
1.52 = -log( x/0.300 )
x/0.300 =
x/0.300 = 0.0301995
we cross multiply
x = 0.300 × 0.0301995
x = 0.00906 M
Therefore, the concentration of the solution is 0.00906 M
<u>Answer:</u> The formation of given amount of oxygen gas results in the absorption of 713 kJ of heat.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
Given mass of oxygen gas = 83 g
Molar mass of oxygen gas = 32 g/mol
Putting values in above equation, we get:
For the given chemical equation:
<u>Sign convention of heat:</u>
When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.
By Stoichiometry of the reaction:
When 3 moles of oxygen gas is formed, the amount of heat absorbed is 824.2 kJ
So, when 2.594 moles of oxygen gas is formed, the amount of heat absorbed will be =
Hence, the formation of given amount of oxygen gas results in the absorption of 713 kJ of heat.