The number of 30- period until the value if the give card be equal is 20 30- day period
<h3>How to write and solve equation</h3>
let
- Number of 30- day period = x
Card 1:
50 - 2x
Card 2:
40 - 1.50x
50 - 2x = 40 - 1.50x
50 - 40 = -1.50x + 2x
10 = 0.50x
- divide both sides by 0.50
x = 10/0.50
x = 20
In conclusion, it will take 20 30- day period until the value of the given card can be equal.
Complete question:
Tavon has a $50 gift card that loses $2 for each 30-day period it is not used. He has a $40 card that loses $1.50 for each 30-day period it is not used.
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Answer:
With something like this you have to start out with 3 givens. what I do for these specific kinds of questions is just put something random in the first half, then put something random twice in the second slot, click clear, then it'l give you a button that says "clear" then a little after it'll say "hint" or "demo" the click those buttons and just put the second half in something random until it pops off, this works every time and will allow you to go to the next task.
Step-by-step explanation:
May I have brainliest please? :)
G(x)= -3x+4
substitute x with -2
g(-2)= -3(-2)+4= 6+4=10
substitute x with 4
g(4)= -3·4+4= -12+4= -8
so g( -2)=10 and g(4) = -8
The value of g(-2) is larger than the value of g(4)
Answer:
Outlier therefore could only be values below - 12.75
or could only be values above + 121.125
Step-by-step explanation:
0, 4, 6, 14, 17
inner quartile range of 0 - 17 is 1/2 of 17 subtracted from the higher number = 17 - 1/2 of 8.5 = 8.5 - 4.25 = 4.25 - 4.25 x 3
= 4.25 to 12.75 for inner quartile
inner quartile range is 12.75-4.25 = 8.5
We then 1.5 x 8.5 to show the outlier
= 12.75 meaning there is no outlier if is below.
Lower quartile fences = 4.25 - 1.5 = 2.75
or -1.5 x 8.5 (the range) = -12.75
Upper quartile fence = 12.75 + 1.5 = 14.25 x 8.5 = 121.125 this would be an outlier if it is 12.75 higher than 121.125 or 12.75 lower than 5.50.
Outlier therefore could only be values below - 12.75
or could only be values above + 121.125
An observation is considered an outlier if it exceeds a distance of 1.5 times the interquartile range (IQR) below the lower quartile or above the upper quartile. The values of the lower quartile - 1.5 x IQR and upper quartile + 1.5 x IQR are known as the inner fences.
An observation is an outlier if it falls more than above the upper quartile or more than below the lower quartile. The minimum value is so there are no outliers in the low end of the distribution. The maximum value is so there are no outliers in the high end of the distribution.
6 to the fourth power is 1296 because 6x6x6x6 gives you 1296
