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Naddika [18.5K]
3 years ago
9

The endpoints of a regular pentagon are (-1,4) and (2,3). What is the perimeter of the Pentagon?

Mathematics
1 answer:
ryzh [129]3 years ago
4 0

the assumption being that the endpoints are two continuous points in the pentagon, Check picture below.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-1}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[2-(-1)]^2+[3-4]^2}\implies d=\sqrt{(2+1)^2+(3-4)^2} \\\\\\ d=\sqrt{9+1}\implies d=\sqrt{10}~\hfill \stackrel{\stackrel{~\hfill \stackrel{\textit{5 sides}}{}}{\textit{perimeter of the pentagon}}}{5\sqrt{10}}

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The function P(x) = –0.015x^2 + 1.2x – 11.5 gives the profit, in thousands of dollars, when a company sells a new product at x d
dlinn [17]

Answer:

The profit decreases by $ 375 for every $ 1 increase in the selling price.

Step-by-step explanation:

From the definition of the secant line we get that the average rate of change of P(x) = -0.015\cdot x^{2}+1.2\cdot x -11.5, where x is the selling price of the product, measured in dollars per unit, is:

r = \frac{P(55)-P(50)}{55-50} (1)

Now we evaluate the function at each bound:

x = 50

P(50) = -0.015\cdot (50)^{2}+1.2\cdot (50)-11.5

P(50) = 11

x = 55

P(55) = -0.015\cdot (55)^{2}+1.2\cdot (55)-11.5

P(55) = 9.125

Then, the average rate of change is:

r = \frac{9.125-11}{55-50}

r = -0.375

Hence, the profit decreases by $ 375 for every $ 1 increase in the selling price.

8 0
2 years ago
What are the solutions to x2 + 8x + 7 =0?
Nata [24]

The chosen topic is not meant for use with this type of problem. Try the examples below.

y = x+4

y = 2x-5

y = x-1

7 0
3 years ago
Does 4/6 have equal parts
Svet_ta [14]

Answer:

yes

Step-by-step explanation:

4/6 of 100 = 66.6666666667

6 0
3 years ago
Find the volume of the triangular prism
Marianna [84]
63 m3

9×2=18

18×7=126

126÷2=63
7 0
3 years ago
Find the inequality represented by the graph.
iris [78.8K]

Answer:

<h2>x \geqslant  \frac{y + 4}{3}</h2>

Explanation;

Associated line with this equation is:

y=mx+c

when,

X=0

y=-4

so, c=-4

X=1

y=-1

- 1 = m- 4 \\  - m =  - 4 + 1 \\  - m =  - 3 \\ m =3 \\

y = 3x - 4 \\ or \: y + 4 = 3x \\ or \:  \frac{y + 4}{3}  = x

Inequality representated by graph:

x \geqslant  \frac{y + 4}{3}

Hope this helps...

Good luck on your assignment...

7 0
3 years ago
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